基于json path删除/修改json对象的java库是什么,或者如何在JsonPath中修复以下问题?

{
  "PersonalDetailsDTO": {
    "FirstName": "Mark",
    "LastName": "Sully",
    "TotalDependent": "2",
    "DOB": "19811212",
    "SecQuestion": "Some Que",
    "SecAnswer": "Some-Ans",
    "Mobile": "0123456789",
    "Email": "some@validemail.com",
    "Title": "Mr",
    "EmploymentListDTO": [
      {
        "Type": "Full-time",
        "Probation": true
      }
    ],
    "AddressListDTO": [
      {
        "AddressType": "BUS",
        "PostCode": "1234",
        "State": "NSW",
        "StreetName": "miller",
        "StreetNumber": "111",
        "StreetType": "Invalid",
        "Suburb": "Sydney",
        "UnitNumber": "Maximum"
      }
    ]
  }
}

我想删除元素$。PersonalDetailsDTO.AddressListDTO.PostCode.

http://static.javadoc.io/com.jayway.jsonpath/json-path/2.2.0/com/jayway/jsonpath/JsonPath.html

所以我写了下面的代码:

public static void main(String[] args) {
    // Prints "Hello, World" to the terminal window.
    String jsonString = "{\n" +
            "  \"PersonalDetailsDTO\": {\n" +
            "      \"FirstName\":\"Mark\",\n" +
            "      \"LastName\":\"Sully\",\n" +
            "      \"Title\":\"Mr\",\n" +
            "      \"DOB\":\"19811201\",\n" +
            "    \"SecQuestion\":\"Some Ques\",\n" +
            "    \"SecAnswer\":\"Some-Ans\",\n" +
            "    \"Email\":\"some@validemail.com\",\n" +
            "    \"EmploymentListDTO\": [\n" +
            "      {\n" +
            "        \"Type\": \"Full-time\",\n" +
            "        \"Probation\": true\n" +
            "      }\n" +
            "    ],\n" +
            "    \"AddressListDTO\": [\n" +
            "      {\n" +
            "        \"AddressType\": \"Residential\",\n" +
            "        \"PostCode\": \"2345\",\n" +
            "        \"State\": \"NSW\",\n" +
            "        \"StreetName\": \"MEL\",\n" +
            "        \"StreetNumber\": \"2\",\n" +
            "        \"StreetType\": \"Boulevard\",\n" +
            "        \"Suburb\": \"Melbourne\",\n" +
            "        \"UnitNumber\": \"345\"\n" +
            "      }\n" +
            "     ]\n" +
            "   }  \n" +
            "}";

    JSONObject jsonObject = new JSONObject(jsonString);
    System.out.println("Before: " + jsonObject.toString());

    JsonPath jp = JsonPath.compile("$.PersonalDetailsDTO.AddressListDTO[0].PostCode");
    Configuration conf = Configuration.defaultConfiguration();
    Object json = conf.jsonProvider().parse(jsonString);
    System.out.println("After: " + jp.delete(json, conf).toString());
}

控制台日志显示:

Before: {"PersonalDetailsDTO":{"EmploymentListDTO":[{"Type":"Full-time","Probation":true}],"SecAnswer":"Some-Ans","Email":"some@validemail.com","SecQuestion":"Some Ques","FirstName":"Mark","DOB":"19811201","AddressListDTO":[{"StreetName":"MEL","Suburb":"Melbourne","State":"NSW","StreetNumber":"2","UnitNumber":"345","AddressType":"Residential","PostCode":"2345","StreetType":"Boulevard"}],"Title":"Mr","LastName":"Sully"}}


After: {PersonalDetailsDTO={FirstName=Mark, LastName=Sully, Title=Mr, DOB=19811201, SecQuestion=Some Ques, SecAnswer=Some-Ans, Email=some@validemail.com, EmploymentListDTO=[{"Type":"Full-time","Probation":true}], AddressListDTO=[{"AddressType":"Residential","State":"NSW","StreetName":"MEL","StreetNumber":"2","StreetType":"Boulevard","Suburb":"Melbourne","UnitNumber":"345"}]}}

查看.toString()在前后大小写中生成的json字符串,

我注意到尽管JsonPath声称接受java.lang.Object作为许多函数中的参数,它真正接受的是一个叫做“jsonProvider”的东西。不确定它是否导致了奇怪的.toString()行为。

不管怎样,有人知道如何从JsonPath api(如remove()、put()、read()等)中获取一个格式良好的json字符串吗?或者将返回值转换为JSONObject之类的东西?

如果您知道其他可以通过json路径删除/修改元素的Java库,请随时推荐。谢谢您!