在线程之间发送Nalgebra向量

我在用Nalgebra的 VectorN<f64, N> 输入一些运行良好的单线程代码。我现在正在尝试多线程算法的各个部分,但是遇到了传递 VectorN 变成一个 thread::spawn 打电话来。例如,以下代码无法编译:

use std::thread;
use nalgebra::{VectorN, DefaultAllocator, DimName};
use nalgebra::allocator::Allocator;

struct Test<N>
where
    N: DimName,
    DefaultAllocator: Allocator<f64, N>,
{
    pub field: VectorN<f64, N>,
}

impl<N> Test<N>
where
    N: DimName,
    DefaultAllocator: Allocator<f64, N>,
{
    pub fn test(&self) {
        let handle = thread::spawn(move || {
            let thing = self.field;

            let thing2 = thing * 2.0;

            thing2
        });

        let res = handle.join().unwrap();
    }
}

出现此错误时:

error[E0277]: `<nalgebra::base::default_allocator::DefaultAllocator as nalgebra::base::allocator::Allocator<f64, N>>::Buffer` cannot be sent between threads safely
  --> trajectories/src/path/mod.rs:34:22
   |
34 |         let handle = thread::spawn(move || {
   |                      ^^^^^^^^^^^^^ `<nalgebra::base::default_allocator::DefaultAllocator as nalgebra::base::allocator::Allocator<f64, N>>::Buffer` cannot be sent between threads safely
   |
   = help: within `nalgebra::base::matrix::Matrix<f64, N, nalgebra::base::dimension::U1, <nalgebra::base::default_allocator::DefaultAllocator as nalgebra::base::allocator::Allocator<f64, N>>::Buffer>`, the trait `std::marker::Send` is not
implemented for `<nalgebra::base::default_allocator::DefaultAllocator as nalgebra::base::allocator::Allocator<f64, N>>::Buffer`
   = note: required because it appears within the type `nalgebra::base::matrix::Matrix<f64, N, nalgebra::base::dimension::U1, <nalgebra::base::default_allocator::DefaultAllocator as nalgebra::base::allocator::Allocator<f64, N>>::Buffer>`
   = note: required by `std::thread::spawn`

我试过各种各样的定义 N 和 DefaultAllocator 在 where 条款,但还没走远。各种各样的搜索引擎在这个问题上没有发现任何有用的东西。

如果我换了 矢量<f64,N> 具有 VectorN<f64, U3> (或任何其他 U* 从Nalgebra输入),上述错误消失。我读过 Nalgebra generic programming guide 不过,这似乎已经过时了,也许不是我需要的;我不想 完成 通用性,就是使用 矢量 任何尺寸的装订。我需要在我的结构上设置什么特征边界才能通过 field 变成一条线?