如何获取用户在'之后输入的命令行参数整数的GCD/a、 有什么顺序吗?

我已经清理干净了,这应该对你有用:

在考虑在代码中计算之前初始化每个变量。

#include<stdio.h>
#include<string.h>

//Main Method
int main(int argc, char *argv[]){

//Declared variables here and print statements
 int i,x,y,gcd;
 printf("Number of command line args is %d\n", argc);
 printf("The GCD is:\t");
 x=atoi(argv[1]);
 for(i=2;i<argc;i++){
    y=atoi(argv[i]);
    while( x !=0 && y !=0 && y != x){
        if(x<y){
            y=y-x;
        }else if(y<x){
            x=x-y;
        }
    }
    gcd=x;
 }
 printf("%d",gcd);
}//End of MAIN

如果您想使用递归。

#include<stdio.h>
#include<string.h>

int GCD(int numbers[], int count)
{
    if (count==1)
        return numbers[0];
    int i, j, min, x, y;
    x = numbers[0];
    y = numbers[1];
    min = (x>y)?x:y;
    for(i=min;i>=1;--i){
        if(x%i==0 && y%i==0){
            int newNumbers[count-1];
            newNumbers[0]=i;
            for (j=1; j<count-1; j++) {
                newNumbers[j] = numbers[j+1];
            }
            return GCD(newNumbers, count-1);
        }
    }
    return 0;
}

int main(int argc, const char * argv[]) {
    //Declared variables here and print statements
    int i;
    printf("Number of command line args is %d\n", argc);
    printf("The GCD is:\t");

    int numbers[argc];

    for(i=1;i<argc;i++){
        numbers[i]=atoi(argv[i]);
    }

    int result = GCD(numbers, argc);
    printf("%d\n", result);

}