如何在DB查询中区分403和404

我正在开发REST API。尝试访问资源时:我们希望给出403(禁止)或404(未找到)错误。我们的桌子是:

CREATE TABLE `Action` (
      `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
      `created_By_Id` int(10) unsigned NOT NULL,
      `name` varchar(60) NOT NULL,
      `updated_action_at` datetime(3) DEFAULT NULL,
      `created_At` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
      `notes` varchar(400) DEFAULT NULL,
       PRIMARY KEY (`id`),
       KEY `action_empId_fk` (`created_By_Id`),
       CONSTRAINT `action_empId_fk` FOREIGN KEY (`created_By_Id`)
       REFERENCES `Employee` (`id`) ON DELETE CASCADE,
       ) ENGINE=InnoDB AUTO_INCREMENT=502004 DEFAULT CHARSET=latin1


CREATE TABLE `ActionAssignedTo` (
    `action_Id` int(10) unsigned DEFAULT NULL,
    `assignee_Id` int(10) unsigned DEFAULT NULL,
     KEY `actionassignedto_emp_id_foreign` (`emp_Id`),
     KEY `actionassignedto_action_id_foreign` (`action_Id`),
     CONSTRAINT `ActionAssignedTo_ibfk_1` FOREIGN KEY (`assignee_Id`) 
     REFERENCES `Employee` (`id`) ON DELETE CASCADE,
     CONSTRAINT `ActionAssignedTo_ibfk_2` FOREIGN KEY (`action_Id`) 
     REFERENCES `Action` (`id`) ON DELETE CASCADE
     ) ENGINE=InnoDB DEFAULT CHARSET=latin1

CREATE TABLE `Employee` (
    `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
    `vendor_Id` int(10) unsigned DEFAULT NULL,
    `name` varchar(40) NOT NULL,
    `mobile_Number` varchar(15) NOT NULL,
    `active` tinyint(1) DEFAULT '1',
    `updated_At` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
    `created_At` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
    PRIMARY KEY (`id`),
    KEY `employee_vendor_id_foreign` (`vendor_Id`),
    CONSTRAINT `employee_vendor_id_foreign` FOREIGN KEY (`vendor_Id`)
    REFERENCES `Vendor` (`vendor_Id`)
    ) ENGINE=InnoDB AUTO_INCREMENT=511 DEFAULT CHARSET=latin1

我们正在运行一个查询,以获取id为9、供应商id为1的创建者员工执行的id为17的操作,该员工已创建该操作,以便可以查看该操作(业务规则)。可以将操作分配给多个员工。

select     Action.name,  
           group_concat(AssigneeNameTable.name) as assignedTo, 
           group_concat(AssigneeNameTable.id) as assignedToId, 
           ActionAssignedTo.action_Id as actionId
from       Action
inner join Employee
on         Action.created_By_Id = Employee.id
and        Employee.vendor_Id = 1 
inner join ActionAssignedTo 
on         Action.id = ActionAssignedTo.action_Id 
and        ActionAssignedTo.action_Id = 17 
inner join Employee as AssigneeNameTable 
on         ActionAssignedTo.assignee_Id = AssigneeNameTable.Id 
where      Action.created_By_Id = 9 
and        Action.deleted_at is null 
group by   Action.id 
limit       2

现在,假设操作在DB中根本不存在-->在这种情况下,上述查询返回空的结果集

the problem is we can not differentiate the query return empty set because 

1. either the action with id:17 did not exist(404- Not Found) 

2. or the business rule failed (as in the person requested the action was not    
at all related to the action(403 - Forbidden).

我能想到的解决方案之一是: 首先运行一个小查询,如:

select * from Action where id = 17

如果此查询返回一个空集,则表示该操作在数据库中不存在。

在此之后,我运行更大的查询

结果集的不同组合(数组中的数字表示返回的记录):

Small Query | Big Query  | Interpretation
---------------------------------------
[0]         | [0]        | Resource Not Found(404)
[1]         | [0]        | Forbidden (403)

如果小查询返回0结果-->我们可以直接发送404错误;否则,我们将执行大查询。