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针对RSA算法的python包

encryption-asymmetric privacy rsa cryptography python

3

amwinter · 技术社区 · 15 年前

希望在python中对短字符串进行RSA加密。这是为了一个用户数据,我想存储没有工作人员(包括我自己)能够看到它。私人钥匙会放在我的保险箱里的拇指驱动器上,等我们被传唤时用。

我的问题: 对于非对称密钥RSA,是否有“可能正确”的python包?使用C库更安全吗(如果是的话,是哪个库)。

4 回复 | 直到 13 年前

1

Omnifarious 15 年前

使用RSA加密短字符串可能有问题。您可以使用RSA加密某些数据,这些数据可以显示有关您的私钥的详细信息。在您的情况下,这可能是好的,因为它将足够模糊,您的工作人员不会发现它。但是,在一般情况下,对于一个知识渊博和/或资金充足的对手,如果您希望将数据保密,则不希望使用RSA直接加密数据。

我建议你只用 gnupg 相反。它帮你解决了所有的问题。

2

3

Barry Wark 15 年前

PyCrypto

3

2

unutbu 15 年前

pycryptopp

4

1

Tim Cooper 13 年前

def gcd (a, b):
    "Compute GCD of two numbers"

    if b == 0: return a
    else: return gcd(b, a % b)

def multiplicative_inverse(a, b):
    """ Find multiplicative inverse of a modulo b (a > b)
        using Extended Euclidean Algorithm """

    origA = a
    X = 0
    prevX = 1
    Y = 1
    prevY = 0

    while b != 0:

        temp = b
        quotient = a/b
        b = a % b
        a = temp

        temp = X
        a = prevX - quotient * X
        prevX = temp

        temp = Y
        Y = prevY - quotient * Y
        prevY = temp

    return origA + prevY

def generateRSAKeys(p, q):
    "Generate RSA Public and Private Keys from prime numbers p & q"

    n = p * q
    m = (p - 1) * (q - 1)

    # Generate a number e so that gcd(n, e) = 1, start with e = 3
    e = 3

    while 1:

        if gcd(m, e) == 1: break
        else: e = e + 2

    d = multiplicative_inverse(m, e)   

    # Return a tuple of public and private keys 
    return ((n,e), (n,d))           

if __name__ == "__main__":

    print "RSA Encryption algorithm...."
    p = long(raw_input("Enter the value of p (prime number):"))
    q = long(raw_input("Enter the value of q (prime number):"))

    print "Generating public and private keys...."
    (publickey, privatekey) = generateRSAKeys(p, q)

    print "Public Key (n, e) =", publickey
    print "Private Key (n, d) =", privatekey

    n, e = publickey
    n, d = privatekey

    input_num = long(raw_input("Enter a number to be encrypted:"))
    encrypted_num = (input_num ** e) % n
    print "Encrypted number using public key =", encrypted_num
    decrypted_num = encrypted_num ** d % n
    print "Decrypted (Original) number using private key =", decrypted_num