Python如何将n个元素的组从列表转换为它们的平均值

1.使用 lists 和 numpy.mean :

import numpy as np
l = [1,2,3,4,5,6,7,8,9,10,11]
l = [l[x:x+3] for x in range(0,len(l),3)]
new = [np.mean(lst) for lst in l]

print(new)

输出:

[2.0, 5.0, 8.0, 10.5]

:

+-------------+----------------+
| List Length | Time Taken (s) |
+-------------+----------------+
|     1000    |      0.01      |
|    10000    |      0.05      |
|    100000   |      0.50      |
|   1000000   |      5.65      |
+-------------+----------------+

numpy arrays 和 :

import numpy as np

l = np.array([1,2,3,4,5,6,7,8,9,10,11])
l = [l[x:x+3] for x in range(0,len(l),3)]
new = [np.mean(lst) for lst in l]

print(new)

性能:

+-------------+----------------+
| List Length | Time Taken (s) |
+-------------+----------------+
|     1000    |      0.005     |
|    10000    |      0.03      |
|    100000   |      0.28      |
|   1000000   |      2.30      |
+-------------+----------------+

第二种方法比第一种方法快得多。因此,我强烈建议你采用第二种方法。