首次访问属性且支持字段成员为空时的编码样式

除非容易出错或耗时,否则我建议在构造函数中填充属性。否则,我建议使用 Lazy<T> 为此,为了螺纹安全:

public class MyClass
{
    private Address _address;

    public MyClass()
    {
        _address = GetAddress();
    }

    public Address Address {get {return _address;}}
}

使用 懒惰(<T> :

public class MyClass
{
    private Lazy<Address> _address;

    public MyClass()
    {
        _address = new Lazy<Address>(() => GetAddress());
    }

    public Address Address {get {return _address.Value;}}
}

从c#6开始,您可以有这样一个自动实现的属性,但接下来必须 GetAddress() 方法 static :

public Address Addgress {get;} = GetAddress();

这将转化为我展示的第一个选项- See SharpLab demo.

您可以使用一种简单的方法来稍微干燥属性代码:

private T GetInstance<T>(ref T instance, Func<T> getInstance)
{
    if (instance == null)
        instance = getInstance();
    return instance;
}

private Address _address;
public Address Address => GetInstance<Address>(ref _address, () => GetAddress());

private string _name;
public string Name => GetInstance<string>(ref _name, () => GetName());

编辑:在查看了@Zohar在评论中善意指出的文章后,我希望使用 Lazy 是一种更好的方法,因为您可以获得具有良好性能的线程安全性。因此,为了使其看起来尽可能整洁(IMO),这将如下所述:

private readonly Lazy<Address> _address = new Lazy<Address>(() => GetAddress());
public Address Address => _address.Value;

在构造函数本身中指定属性值,如下所示

private Address _address;
public Address Address
{
  get { return _address; }
}

public ABC() //Constructor 
{
  _address = GetAddress();
}