JavaScript表单提交()完成

<form onsubmit="return controlParentForm();" id="parentForm">
...
</form>

JS:

var controlSubmitParentForm = 0;
function controlParentForm(){

   var ret = false;

   if (controlSubmitParentForm==0){

     controlSubmitParentForm = 1;
     document.frames.IFRAME_Items.document.forms[0].submit();
     setTimeout(controlParentForm, 200);

   }
   else if (controlSubmitParentForm==1){

     if (document.frames.IFRAME_Items.document.readyState=="complete"){
        controlSubmitParentForm = 2;
        document.getElementById("parentForm").submit();
     }
     setTimeout(controlParentForm, 200);

   }
   else if (controlSubmitParentForm==2){
       // controls for "parentForm"
       ret = true;
       controlSubmitParentForm = 0;
   }

   return ret;

}

您所能做的最好的事情是在 jQuery Form plugin . 这样,您就可以等待响应返回。它还提供了一个 success