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当我执行驱动程序时,Selenium会将我重定向回起始页。获取(url)

selenium-chromedriver web-scraping selenium python-3.x

Pygirl · 技术社区 · 7 年前

我正在删除此网页: http://www.cpcb.gov.in/CAAQM/frmReportdisplay.aspx 单击“提交”按钮后,页面内容会发生更改,而url保持不变。我想访问这些内容,但在打印(driver.current\u url)时无法访问,因为我看到了起始页的内容。如何访问这些内容?

提交后: 页面内容就是这个。

from bs4 import BeautifulSoup
import sys
from selenium import webdriver
from selenium.webdriver.support.ui import Select
import time 
chromedriver_loc = '/home/ninjakx/Desktop/mywork/chromedriver-Linux64' 
# enter path of chromedriver
driver = webdriver.Chrome(executable_path=chromedriver_loc)
url ="http://www.cpcb.gov.in/CAAQM/frmUserAvgReportCriteria.aspx"
driver.get(url)

select = Select(driver.find_element_by_id('ddlState'))
# select by visible text
select.select_by_visible_text('Delhi')
time.sleep(10)
select = Select(driver.find_element_by_id('ddlCity'))
select.select_by_visible_text('Delhi')
time.sleep(5)
select = Select(driver.find_element_by_id('ddlStation'))
select.select_by_visible_text('Dwarka')
time.sleep(10)

your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)
your_choice=driver.find_element_by_xpath("//select[@id='lstBoxChannelLeft']/option[@value='874']")
your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)
your_choice=driver.find_element_by_xpath("//select[@id='lstBoxChannelLeft']/option[@value='1366']")
your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)
your_choice=driver.find_element_by_xpath("//select[@id='lstBoxChannelLeft']/option[@value='1377']")

your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)
your_choice=driver.find_element_by_xpath("//select[@id='lstBoxChannelLeft']/option[@value='864']")
your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)
your_choice=driver.find_element_by_xpath("//select[@id='lstBoxChannelLeft']/option[@value='824']")
your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)
your_choice=driver.find_element_by_xpath("//select[@id='lstBoxChannelLeft']/option[@value='502']")
your_choice.click()
driver.find_element_by_xpath('//*[@id="btnAdd"]').click()
time.sleep(13)

datefield = driver.find_element_by_xpath('//*[@id="txtDateFrom"]')
datefield.click()
datefield.clear()
datefield.send_keys("01/01/2017")
time.sleep(2)
driver.find_element_by_xpath('//*[@id="btnSubmit"]').click()
time.sleep(5)
cur_url = driver.current_url
driver.get(url)
time.sleep(20)

2 回复 | 直到 7 年前

Avaricious_vulture 7 年前

这不仅仅是一个打字错误吗?

您键入了:

driver.find_element_by_xpath('//*[@id="btnSubmit"]').click()
time.sleep(5)
cur_url = driver.current_url
driver.get(url)

我认为应该是:

driver.find_element_by_xpath('//*[@id="btnSubmit"]').click()
time.sleep(5)
cur_url = driver.current_url
driver.get(cur_url) #changed here

Pygirl 7 年前

我不必再次访问链接。只需继续编写脚本即可获取数据。