在python中逐个替换字符串

试试这个

x = "threee"
# build a generator expression that yields the position of "e"s
# change "e"s with "x" according to location of "e"s yielded from the genexp
[f"{x[:i]}x{x[i+1:]}" for i in (i for i, e in enumerate(x) if e=='e')]
['thrxee', 'threxe', 'threex']

你可以用发电机来代替 e 具有 x 按顺序遍历字符串。例如:

def replace(string, old, new):
    l = len(old)
    start = 0
    while start != -1:
        start = string.find(old, start + l)
        if start != -1:
            yield string[:start] + new + string[start + l:]

z = replace('threee', 'e', 'x')
for s in z:
    print(s)

输出:

thrxee
threxe
threex

注意,我对代码进行了概括,允许任意长度的匹配和替换字符串,如果不需要,只需替换 l ( len(old) )使用 1 .

def replace(string,old,new):
    f = string.index(old)
    l = list(string)
    i = 0
    for a in range(string.count(old)):
        l[f] = new
        yield ''.join(l)
        l[f]=old
        try:
            f = string.index(old,f+1)
        except ValueError:
            pass
        i+=1


z = replace('threee', 'e', 'x')
for a in z:
    print(a)

输出

thrxee
threxe
threex