代码之家 › 专栏 › 技术社区 › Darren

将对象中的数组转换为单个字符串

javascript

Darren · 技术社区 · 7 年前

我怎样才能分一杯羹 array 属于 images object ?

JSON 在下面怎样才能生产出一种新产品 return string 各 itemUrl productCode

{
  "products": [
    {
      "productCode": "ID1",
      "images": [
        {
          "id": 1,
          "itemUrl": "https://img.com/1.JPG"
        },
        {
          "id": 2,
          "itemUrl": "https://img.com/2.JPG"
        }
      ]
    },
    {
      "productCode": "ID2",
      "images": [
        {
          "id": 3,
          "itemUrl": "https://img.com/3.JPG"
        },
        {
          "id": 4,
          "itemUrl": "https://img.com/4.JPG"
        },
        {
          "id": 5,
          "itemUrl": "https://img.com/5.JPG"
        }
      ]
    }
  ]
}

变成

https://img.com/1.JPG
https://img.com/2.JPG
https://img.com/3.JPG
https://img.com/4.JPG
https://img.com/5.JPG

目前,如果我使用

for (const tour of data.products) {
  console.log(tour.images[0].itemUrl);
  ...

返回

https://img.com/1.JPG
https://img.com/3.JPG

但是,什么时候?

let imageEach = tour.images;
let output = [];
imageEach.forEach(item => {
  output.push(item.itemUrl);
});
  ...

返回 属于

[{
  https://img.com/1.JPG,
  https://img.com/2.JPG
}]

[{
  https://img.com/3.JPG
  https://img.com/4.JPG
  https://img.com/5.JPG
}]

6 回复 | 直到 7 年前

Akrion 7 年前

你可以用这个试试 Array.reduce Array.map 检查项目并获取 itemUrl :

const data = { "products": [ { "productCode": "ID1", "images": [ { "id": 1, "itemUrl": "https://img.com/1.JPG" }, { "id": 2, "itemUrl": "https://img.com/2.JPG" } ] }, { "productCode": "ID2", "images": [ { "id": 3, "itemUrl": "https://img.com/3.JPG" }, { "id": 4, "itemUrl": "https://img.com/4.JPG" }, { "id": 5, "itemUrl": "https://img.com/5.JPG" } ] } ] } 

const result = data.products.reduce((r,{images}) => {
  r.push(...images.map(x => x.itemUrl))
  return r
}, [])
 console.log(result.join('\n'))

或者甚至更短,如@Prassana所建议的,使用ES6阵列扩展更多:

const data = { "products": [ { "productCode": "ID1", "images": [ { "id": 1, "itemUrl": "https://img.com/1.JPG" }, { "id": 2, "itemUrl": "https://img.com/2.JPG" } ] }, { "productCode": "ID2", "images": [ { "id": 3, "itemUrl": "https://img.com/3.JPG" }, { "id": 4, "itemUrl": "https://img.com/4.JPG" }, { "id": 5, "itemUrl": "https://img.com/5.JPG" } ] } ] } 

const result = data.products.reduce((r,{images}) => 
  [...r, ...images.map(x => x.itemUrl)], [])

console.log(result.join('\n'))

holydragon 7 年前

尝试

var result = [];
for (var i = 0; i < data.products.length; i++) {
    for (var j = 0; j < data.products[i].images.length; j++){
        result.push(data.products[i].images[j].itemUrl);
    }
}
console.log(result);

Prasanna 7 年前

你需要 Array.concat

const data = {
  "products": [
    {
      "productCode": "ID1",
      "images": [
        {
          "id": 1,
          "itemUrl": "https://img.com/1.JPG"
        },
        {
          "id": 2,
          "itemUrl": "https://img.com/2.JPG"
        }
      ]
    },
    {
      "productCode": "ID2",
      "images": [
        {
          "id": 3,
          "itemUrl": "https://img.com/3.JPG"
        },
        {
          "id": 4,
          "itemUrl": "https://img.com/4.JPG"
        },
        {
          "id": 5,
          "itemUrl": "https://img.com/5.JPG"
        }
      ]
    }
  ]
}

let urls =  []
data.products.forEach(item => {
  urls = urls.concat(item.images.map(img => img.itemUrl))
})

console.log(urls)

eag845 7 年前

你可以试试这个。

let json = {
  "products": [
    {
      "productCode": "ID1",
      "images": [
        {
          "id": 1,
          "itemUrl": "https://img.com/1.JPG"
        },
        {
          "id": 2,
          "itemUrl": "https://img.com/2.JPG"
        }
      ]
    },
    {
      "productCode": "ID2",
      "images": [
        {
          "id": 3,
          "itemUrl": "https://img.com/3.JPG"
        },
        {
          "id": 4,
          "itemUrl": "https://img.com/4.JPG"
        },
        {
          "id": 5,
          "itemUrl": "https://img.com/5.JPG"
        }
      ]
    }
  ]
}
json.products.forEach(product => {
     console.log(product.productCode + ": ")
     product.images.forEach(i => console.log(i.itemUrl))                       
});

// or 
json.products.forEach(product => {
     product.images.forEach(i => console.log(product.productCode + " : " + i.itemUrl))  
});

Son Tr. 7 年前

products.reduce((urls, product, i) => {
  const imageURLs = product.images.map(img => img.itemUrl);
  urls = urls.concat(imageURLs);
  return urls;
}, []);

试试这个

Akki geek 7 年前

您可以尝试我的代码来产生以下结果

{
 "ID1" : ["https://img.com/1.JPG","https://img.com/2.JPG"],
 "ID2" : ["https://img.com/3.JPG","https://img.com/4.JPG","https://img.com/5.JPG"]
}

 obj.products.reduce((acc, product)=>{
   acc[product.productcode] = product.images.map(img => img.itemUrl)
   return acc
 }, {})