如何在Python中合并来自3个不同列表的嵌套子列表的元素?

您可以使用 zip 两次:

A = [["a", "b", "c"],["f", "b", "a"]]
numbers = [[1, 2 ,3], [1, 2, 3]]
frequency = [[0.2, 0.5, 0.7], [0.1, 0.8, 0.9]]

output = [list(zip(*zipped)) for zipped in zip(A, numbers, frequency)]
print(output)
# [[('a', 1, 0.2), ('b', 2, 0.5), ('c', 3, 0.7)], [('f', 1, 0.1), ('b', 2, 0.8), ('a', 3, 0.9)]]

或者,您可以使用 itertools.starmap 要获取(一个或多个)迭代器,请执行以下操作:

from itertools import starmap

output = starmap(zip, zip(A, numbers, frequency))

for subzip in output:
    print(*subzip)
# ('a', 1, 0.2) ('b', 2, 0.5) ('c', 3, 0.7)
# ('f', 1, 0.1) ('b', 2, 0.8) ('a', 3, 0.9)

使用列表理解(尽管李的回答更简洁):

result=[[(i,k,j)  for i,k,j in zip(q,w,e)]
        for q,w,e in zip(A,numbers,frequency)]

使用 for 回路:

result=[]
for q,w,e in zip(A,numbers,frequency):
    temp=[]
    for i,k,j in zip(q,w,e):
        temp.append((i,k,j))
    result.append(temp)