使用-beautiful soup在python的表列中获取href链接

迭代 <td> <td> 有 <a> ( if td.a .get('href') 属于 td.a :

from bs4 import BeautifulSoup
import requests
try:
    r = requests.get('https://coinmarketcap.com/')
    soup = BeautifulSoup(r.text, 'lxml')

    table = soup.find('table', class_='cmc-table')

    for row in table.tbody.find_all('tr'):
        # Find all data for each column
        columns = row.find_all('td')
        for td in columns:
            if td.a:
                print(td.a.get('href'))
                # theoretically for performance you can
                # break
                # here to stop the loop if you expect only one anchor link per `td`

except requests.exceptions.RequestException as e:
    print(e)

<a> ,选择它并获取其 href :

link = columns[2].a['href']

实例

from bs4 import BeautifulSoup
import requests
try:
    r = requests.get('https://coinmarketcap.com/')
    soup = BeautifulSoup(r.text, 'lxml')

    
    table = soup.find('table', class_='cmc-table')
    for row in table.tbody.find_all('tr'):    
        # Find all data for each column
         columns = row.find_all('td')
         link = columns[2].a['href']
         print(link)
         
except requests.exceptions.RequestException as e:
    print(e)