在Django中如何按对象的日期对其进行分组?

下面是ignacio建议使用的一个工作示例 itertools.groupby .

class Article(object):
    def __init__(self, pub_date):
        self.pub_date = pub_date


if __name__ == '__main__':
    from datetime import date
    import itertools
    import operator

    # You'll use your Article query here instead:
    # a_list = Article.objects.filter(pub_date__lte = date.today())
    a_list = [
        Article(date(2010, 1, 2)),
        Article(date(2010, 2, 3)),
        Article(date(2010, 1, 2)),
        Article(date(2011, 3, 2)),
    ]


    keyfunc = operator.attrgetter('pub_date')

    a_list = sorted(a_list, key = keyfunc)
    group_list = [{ k.strftime('%Y-%m-%d') : list(g)} 
                  for k, g in itertools.groupby(a_list, keyfunc)]

    print group_list

[{'2010-01-02': [<__main__.Article object at 0xb76c4fec>, <__main__.Article object at 0xb76c604c>]}, {'2010-02-03': [<__main__.Article object at 0xb76c602c>]}, {'2011-03-02': [<__main__.Article object at 0xb76c606c>]}]

itertools.groupby()

也许你应该在模板级别做?如果是这样,您只需要: regroup tempalte tag