在Python中将静态方法的输出分配给静态变量

这在Python 3.6上完美地运行:

class A:
   arr = []

   @staticmethod
   def fillArr():
       #do more stuff but for simplicity...
       A.arr = [[2,2,2,]]

A.fillArr()

print (A.arr)

或者,在您的评论中添加额外信息:

class A:
    arr = []

    @staticmethod
    def fillArr():
        #do more stuff but for simplicity...
        A.arr = [[2,2,2,]]

    def __init__ (self):
        if not A.arr:
           A.fillArr ()

A ()

print (A.arr)

class A( object ):
  arr = []

  @classmethod
  def FillArr( cls ):
    cls.arr = [[2,2,2]]

A.FillArr()

print A.arr

这将导致:[[2,2,2]]

/ 编辑 /

class A
   arr=[]

   def FillArr( self ):
     self.arr = [[2,2,2,]]

   def __init__( self ):
     self.FillArr()

a = A()
print a.arr