从字典[副本]创建“顶级列表”

通过字典值进行简单排序:

x = {"John":15, "Josh":2, "Emily":50, "Joey":12}

for i, t in enumerate(sorted(x.items(), key=lambda x: x[1], reverse=True), 1):
    print('{}. {} - {}'.format(i, t[0], t[1]))

输出:

1. Emily - 50
2. John - 15
3. Joey - 12
4. Josh - 2

在此处查看答案: How do I sort a dictionary by value?

在您的情况下,您需要先反转sorted\u x,因为您需要更高的值,所以:

import operator


x = {"John":15,"Josh":2,"Emily":50,"Joey":12}
sorted_x = sorted(x.items(), key=operator.itemgetter(1), reverse=True)

简单的方法:

x = {"John":15,"Josh":2,"Emily":50,"Joey":12}

val = sorted([y for y in x.values()])
name = val[:]
for key in x.keys():
    id = val.index(x[key])
    name[id] = key