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javascript Twilio聊天SDK上的身份禁止访问

twilio

jonatasdaniel · 技术社区 · 8 年前

我正在使用twilio聊天javascript SDK,当我尝试创建新频道并邀请用户时遇到了问题。错误:身份禁止访问

但如果我转到仪表板,通道是由2个成员创建的。

PS:我正在创建TwilioAPI上列出的用户令牌,我认为令牌不会有问题,因为消息已经发送了。

我创建频道的代码:

this.client.createChannel({
  uniqueName: roomName,
  friendlyName: 'My Channel',
  type: 'private'
}).then(channel => {
  this.channel = channel
  this.channel.join()
});

this.channel.invite(user)

并生成用户令牌:

new Fingerprint2().get(fingerprint => {
  this.fingerprint = fingerprint

  let AUTH_TOKEN = $('meta[name=csrf-token]').attr('content')

  fetch('/chat/tokens', {
    method: 'POST',
    body: JSON.stringify({
      fingerprint: fingerprint,
      authenticity_token: AUTH_TOKEN,
      email: email
    }),
    headers: {
      'X-Requested-With': 'XMLHttpRequest',
      'X-CSRF-Token': $('meta[name="csrf-token"]').attr('content'),
      'Content-Type': 'application/json',
      'Accept': 'application/json'
    }
  }).then(result => result.json()).then(data => {
    callback({ token: data.token, username: data.username })
  })
})

在我的API上

user = User.find_by_email(params[:email])

account_sid = ENV['TWILIO_ACCOUNT_SID']
api_key = 'SKe9fcdbefe0bdc1f01af4aa50d3548b70'
api_secret = 'oslALMC18tCZrUhBRDPin5KbqPSR9Rr4'

service_sid = ENV['TWILIO_SERVICE_ID']
device_id = params[:fingerprint]
identity = user.username
endpoint_id = "FakeEndPoint:#{identity}:#{device_id}"

grant = Twilio::JWT::AccessToken::IpMessagingGrant.new
grant.service_sid = service_sid
grant.endpoint_id = endpoint_id

token = Twilio::JWT::AccessToken.new(
  account_sid,
  api_key,
  api_secret,
  [grant],
  identity: identity
)

render status: 200, json: { token: token.to_jwt, username: user.username }

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1 回复 | 直到 8 年前

philnash 8 年前

Twilio开发者布道者。

当你加入一个频道时 channel.join()

相反,你应该倾听 channelJoined event on the chat client 一旦触发,你可以确定你现在是该频道的一员,并且可以与之互动。

this.client.on('channelJoined', function(channel) {
  console.log('Joined channel ' + channel.friendlyName) 
})

this.client.createChannel({
  uniqueName: roomName,
  friendlyName: 'My Channel',
  type: 'private'
}).then(channel => {
  this.channel = channel
  this.channel.join()
});

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