R-使用带FOR循环的ASSIGN时如何删除NAs?

你可以用 keywordsDF[[keywordList[i]]] 任何你想去的地方 keywordsDF$Consumption ,所以

# spaced to make the substitution line up
consumption =          keywordsDF$Consumption      [!is.na( keywordsDF$Consumption       )]
assign(keywordList[i], keywordsDF[[keywordList[i]]][!is.na( keywordsDF[[keywordList[i]]] )]

assign 这样地。。。一份清单可能更好,比如 kw_no_na = lapply(keywordsDF[keywordList], na.omit) kw_no_na$consumption 或 kw_no_na[["consumption"]] .

na.omit() ?

for (i in seq_along(keywordList)) {
  assign(keywordList[i], na.omit(keywordsDF[keywordList[i]]))
}