带有for/if的Python转换和过滤器列表

是否有一种方法可以在单个列表中转换和过滤,即:

def transform(el):
    if some_condition(el):
        return None

    return complex_logic(el)

def main():
    transformed = [transform(el) for el in some_list if transform(el) != None]

但是不要打电话 transform 两次一、 e.将其分配给变量,类似于(在伪Python中):

def main():
  transformed = [transformed for el in some_list let transformed = transform(el) if transformed != None]