iter = itertools.count() )我可以拿第一个 next(iter) 第一个?
iter = itertools.count()
next(iter)
def rest(iter): next(iter) return (x for x in iter)
first, *rest = iter
但这实现了整个迭代器-- rest
rest
itertools.islice
>>> from itertools import islice >>> [*range(9)] [0, 1, 2, 3, 4, 5, 6, 7, 8] >>> [*islice(range(9), 1, None)] [1, 2, 3, 4, 5, 6, 7, 8]
islice
>>> spam = iter(range(9)) >>> next(spam) 0 >>> [*spam] [1, 2, 3, 4, 5, 6, 7, 8]