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如何处理此文本文件并分析所需内容?

doctest shell parsing python

2

foobarfuzzbizz · 技术社区 · 15 年前

我试图解析python doctest模块中的ouput并将其存储在HTML文件中。

我有类似的输出:

**********************************************************************
File "example.py", line 16, in __main__.factorial
Failed example:
    [factorial(n) for n in range(6)]
Expected:
    [0, 1, 2, 6, 24, 120]
Got:
    [1, 1, 2, 6, 24, 120]
**********************************************************************
File "example.py", line 20, in __main__.factorial
Failed example:
    factorial(30)
Expected:
    25252859812191058636308480000000L
Got:
    265252859812191058636308480000000L
**********************************************************************
1 items had failures:
   2 of   8 in __main__.factorial
***Test Failed*** 2 failures.

每个失败前面都有一行星号,这些星号将每个测试失败彼此分隔开来。

我想做的是去掉失败的文件名和方法,以及预期的和实际的结果。然后我想用这个创建一个HTML文档(或者将它存储在一个文本文件中,然后进行第二轮解析)。

我如何使用python或unix shell实用程序的某些组合来实现这一点?

编辑:我编写了下面的shell脚本,它按照我希望的方式匹配每个块,但是我不确定如何将每个sed匹配重定向到自己的文件。

python example.py | sed -n '/.*/,/^\**$/p' > `mktemp error.XXX`

4 回复 | 直到 15 年前

1

Roberto Bonvallet 15 年前

这是一个快速而脏的脚本,它将输出解析为包含相关信息的元组:

import sys
import re

stars_re = re.compile('^[*]+$', re.MULTILINE)
file_line_re = re.compile(r'^File "(.*?)", line (\d*), in (.*)$')

doctest_output = sys.stdin.read()
chunks = stars_re.split(doctest_output)[1:-1]

for chunk in chunks:
    chunk_lines = chunk.strip().splitlines()
    m = file_line_re.match(chunk_lines[0])

    file, line, module = m.groups()
    failed_example = chunk_lines[2].strip()
    expected = chunk_lines[4].strip()
        got = chunk_lines[6].strip()

    print (file, line, module, failed_example, expected, got)

2

4

Ned Batchelder 15 年前

您可以编写一个python程序来区分这一点,但最好的做法是首先修改doctest以输出您想要的报告。从doctest.doctestrunner的文档中:

                                  ... the display output
can be also customized by subclassing DocTestRunner, and
overriding the methods `report_start`, `report_success`,
`report_unexpected_exception`, and `report_failure`.

3

1

David Raznick 15 年前

我在pyparsing中编写了一个快速的解析器来完成这项工作。

from pyparsing import *

str = """
**********************************************************************
File "example.py", line 16, in __main__.factorial
Failed example:
    [factorial(n) for n in range(6)]
Expected:
    [0, 1, 2, 6, 24, 120]
Got:
    [1, 1, 2, 6, 24, 120]
**********************************************************************
File "example.py", line 20, in __main__.factorial
Failed example:
    factorial(30)
Expected:
    25252859812191058636308480000000L
Got:
    265252859812191058636308480000000L
**********************************************************************
"""

quote = Literal('"').suppress()
comma = Literal(',').suppress()
in_ = Keyword('in').suppress()
block = OneOrMore("**").suppress() + \
        Keyword("File").suppress() + \
        quote + Word(alphanums + ".") + quote + \
        comma + Keyword("line").suppress() + Word(nums) + comma + \
        in_ + Word(alphanums + "._") + \
        LineStart() + restOfLine.suppress() + \
        LineStart() + restOfLine + \
        LineStart() + restOfLine.suppress() + \
        LineStart() + restOfLine + \
        LineStart() + restOfLine.suppress() + \
        LineStart() + restOfLine  

all = OneOrMore(Group(block))

result = all.parseString(str)

for section in result:
    print section

给予

['example.py', '16', '__main__.factorial', '    [factorial(n) for n in range(6)]', '    [0, 1, 2, 6, 24, 120]', '    [1, 1, 2, 6, 24, 120]']
['example.py', '20', '__main__.factorial', '    factorial(30)', '    25252859812191058636308480000000L', '    265252859812191058636308480000000L']

4

0

Sean 15 年前

这可能是我写过的最不优雅的Python脚本之一,但是它应该有一个框架来做您想要做的事情,而不需要借助于Unix实用程序和单独的脚本来创建HTML。它还没有经过测试,但只需要稍作调整就可以了。

import os
import sys

#create a list of all files in directory
dirList = os.listdir('')

#Ignore anything that isn't a .txt file.
#
#Read in text, then split it into a list.
for thisFile in dirList:
    if thisFile.endswith(".txt"):
        infile = open(thisFile,'r')

        rawText = infile.read()

        yourList = rawText.split('\n')

        #Strings
        compiledText = ''
        htmlText = ''

        for i in yourList:

            #clunky way of seeing whether or not current line  
            #should be included in compiledText

            if i.startswith("*****"):
                compiledText += "\n\n--- New Report ---\n"

            if i.startswith("File"):
                compiledText += i + '\n'

            if i.startswith("Fail"):
                compiledText += i + '\n'

            if i.startswith("Expe"):
                compiledText += i + '\n'

            if i.startswith("Got"):
                compiledText += i + '\n'

            if i.startswith(" "):
                compiledText += i + '\n'


    #insert your HTML template below

    htmlText = '<html>...\n <body> \n '+htmlText+'</body>... </html>'


    #write out to file
    outfile = open('processed/'+thisFile+'.html','w')
    outfile.write(htmlText)
    outfile.close()