python查找时间字符串的最大值

尝试 the parse_timespan function from humanfriendly

>>> from humanfriendly import parse_timespan
>>> intervals = ["1 days", "7 days", "30 days"]
>>> parsed_intervals = [parse_timespan(interval) for interval in intervals]
>>> max(parsed_intervals)
2592000.0

如果需要原始格式(而不是进一步处理的时间),还可以使用:

>>> from humanfriendly import parse_timespan
>>> intervals = ["1 days", "7 days", "30 days"]
>>> max(intervals, key=parse_timespan)
'30 days'

我是用电脑做的 pandas 最终。在这里张贴,以防对某人有所帮助。

import pandas as pd
intervals = ["1 days", "7 days", "30 days"]
deltas = [pd.Timedelta(i) for i in intervals]

idx = deltas.index(max(deltas))

这可以通过使用核心python实现(如下所示)。

intervals = ["1 days", "7 days", "30 days"]
numbers_only = [] # creating a list to get the numbers only
for interval in intervals: # iteration through the intervals
    numbers_only.append(int(interval.split(" ")[0])) # splitting each interval on a blank space and appending just the number

max_in_nums = max(numbers_only) # using python's default library max function to get the max number in a list of numbers
print(numbers_only.index(max_in_nums)) # get the index of the number 

intervals = ["1 days", "7 days", "30 days"]
findmax =[]
for i in range(len(intervals)):
    n = intervals[i].replace(' days', '')
    findmax.append(float(n))
print(max(findmax))

此代码应适用于:

result = 0
interval = ''
for i in range(len(intervals)):
    val = int(intervals[i].split(' ')[0])
    if val > result:
        result = val
        interval = i
print(interval)