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将组合框选定值作为另一个控件wpf的dataTemplate的键

controls binding templates wpf

yoav.str · 技术社区 · 15 年前

我有一个组合框:

   <Grid>

    <ComboBox Height="52" HorizontalAlignment="Left"
              ItemsSource="{Binding templatesNames}"
              SelectedValuePath="Type.FullName"         
              Margin="169,43,0,0" Name="comboBox1" 
              VerticalAlignment="Top" Width="148" />

    <Button Content="Button"
   ***Template="{Binding key = Converter={Binding SelectedItem.Value,ElementName=comboBox1}}"
            Height="56" HorizontalAlignment="Left" 
            Margin="191,204,0,0" Name="button1" 
            VerticalAlignment="Top" Width="80" />
</Grid>

问题的签名是 * 我有模板如何保存模板名称我想把这些名字转换成按钮要绑定到的密钥(模板密钥)

我该怎么做?... 转换器应该做什么?需要吗?我可以不用吗?

编辑: 这就是我现在所做的:

    <ComboBox x:Name="ComboBox1"
                              ItemsSource="{Binding collection}" 
                               Margin="553,0,0,13" 
                              SelectedValuePath="Type.FullName" SelectedIndex="1"
                              FontFamily="Buxton Sketch"
                              FontSize="20" HorizontalAlignment="Left" Width="231" Height="46"     VerticalAlignment="Bottom" />

其中collection是public observateCollection collection{get;set;}

按钮类似于@Meleak按钮,项目名称空间是clr namespace:dinamicGridLayout 我应该在converter Uri resourceLocater=new Uri(@“clr namespace:dinamicGridLayout;ResourceDictionary1.xaml”,System.UriKind.Relative);)中写入吗;?

1 回复 | 直到 15 年前

Fredrik Hedblad 15 年前

如果您将所有的控件模板放在资源字典中,您可以使用这样的模板转换器

<ComboBox Height="52" HorizontalAlignment="Left" 
          ItemsSource="{Binding templatesNames}" 
          SelectedValuePath="Type.FullName"          
          Margin="169,43,0,0" Name="comboBox1"  
          VerticalAlignment="Top" Width="148" /> 

<Button Content="Button" 
        Template="{Binding SelectedItem.Value,
                           ElementName=comboBox1,
                           Converter={StaticResource TemplateConverter}}"
        Height="56" HorizontalAlignment="Left"  
        Margin="191,204,0,0" Name="button1"  
        VerticalAlignment="Top" Width="80" />

在转换器中,从资源字典加载ControlTemplate并返回它。

public class TemplateConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        string resourceKey = value.ToString();
        Uri resourceLocater = new Uri("/YourNamespace;component/Dictionary1.xaml", System.UriKind.Relative);
        ResourceDictionary resourceDictionary = (ResourceDictionary)Application.LoadComponent(resourceLocater);
        return resourceDictionary[resourceKey] as ControlTemplate;
    }
    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        return null;
    }
}

更新

如果您的命名空间是dinamicGridLayout,那么转换器应该如下所示

Uri resourceLocater = new Uri("/dinamicGridLayout;component/Dictionary1.xaml", System.UriKind.Relative);

上载的小示例项目 here .