在字符串数组中搜索匹配的字符序列

试试这个

const arr = ["Apple", "Banana", "Cherry", "Orange", "Avocado", "Ananas", "Pineapple"];


const search = query => arr.filter(s => s.toLowerCase().includes(query))

console.log(search("n"))
console.log(search("ppl"))

也有可能是这样

const arr = ["Apple", "Banana", "Cherry", "Orange", "Avocado", "Ananas", "Pineapple"];

const query = 'pp';

arr.filter(element => element.includes(query));

使用filter函数和indexOf非常简单

const arr = ["Apple", "Banana", "Cherry", "Orange", "Avocado", "Ananas", "Pineapple"];
const cond = 'ppl'
console.log(arr.filter(x => x.indexOf(cond) > -1 ))

<script>
function checkPattern(str, pattern) {
    var len = pattern.length;

    if (str.length < len) {
    return false;
    }

    for (var i = 0; i < len - 1; i++) {
    var x = pattern[i];
    var y = pattern[i + 1];

    var last = str.lastIndexOf(x);

    var first = str.indexOf(y);

    if (last === -1 || first === -1 || last > first) {
        return false;
    }
    }

    return true;
}

var str = "engineers rock";
var pattern = "gin";

document.write(checkPattern(str, pattern));
</script>

你可以用 Array.prototype.filter() 与…结合 String.prototype.includes() :

• const result = arr.filter(el => el.toLowerCase().includes(input.toLowerCase()))

代码:

const arr = ["Apple", "Banana", "Cherry", "Orange", "Avocado", "Ananas", "Pineapple"]
const inputs = ["ppl", "n", "voca", "rr", "r"]

inputs.forEach(input => {
  const result = arr.filter(el => el.toLowerCase().includes(input.toLowerCase()))
  console.log(`Result for ${input}:`, result)
})