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无法在python中使用xpath和selenium来单击元素

web-scraping selenium-webdriver selenium python

1

PythonNoob · 技术社区 · 7 年前

我正在尝试Selenium框架,以了解有关Web浏览器自动化的一些内容。因此,我决定建立一个奥迪车型…

我的代码到目前为止:

from selenium import webdriver
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By

chrome_driver = webdriver.Chrome(executable_path=r"chromedriver_win32\chromedriver.exe")
chrome_driver.get("https://www.audi.de/de/brand/de/neuwagen.html")

# choose A3 model
chrome_driver.find_element_by_xpath('//*[@id="list"]/div[1]/ul/li[2]/a[2]').click()

# choose sedan version
WebDriverWait(chrome_driver, 3).until(EC.visibility_of_element_located((By.XPATH, '//*[@id="a3limo"]/div/a'))).click()

# start model configuration
WebDriverWait(chrome_driver, 3).until(EC.visibility_of_element_located((By.XPATH, '/html/body/div[1]/div[2]/div/div[6]/div[2]/div/div[1]/ul/li[1]/a'))).click()

# choose the s-line competition package
WebDriverWait(chrome_driver, 3).until(EC.visibility_of_element_located((By.XPATH, '/html/body/div[1]/div[2]/div/div[7]/div[2]/div[2]/div[3]/div[1]/div/div[1]/div/div[1]/span/span'))).click()

# accept the s-line competition package
WebDriverWait(chrome_driver, 3).until(EC.visibility_of_element_located((By.XPATH, '/html/body/div[5]/div/div/div/div/div/ul[2]/li[2]/a'))).click()

现在,代码已经在线失败了 start model configuration (参见网页上的“Konfiguration Starten”按钮 https://www.audi.de/de/brand/de/neuwagen/a3/a3-limousine-2019.html )xpath必须是正确的,元素也应该是可见的,那么我在这里做了什么错误呢?

2 回复 | 直到 7 年前

1

QHarr 7 年前

以下内容似乎对我有用。我添加了waitiesforelements,并通过javascript模拟了元素的点击。

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

url = 'https://www.audi.de/de/brand/de/neuwagen.html'
d = webdriver.Chrome()
d.get(url)
WebDriverWait(d,10).until(EC.presence_of_element_located((By.CSS_SELECTOR, '[data-filterval="a3"]'))).click()
d.get(WebDriverWait(d,10).until(EC.presence_of_element_located((By.CSS_SELECTOR, '#a3limo .mf-model-details a'))).get_attribute('href'))
element = WebDriverWait(d,10).until(EC.presence_of_element_located((By.CSS_SELECTOR, '[title="Konfiguration starten"]')))
d.execute_script("arguments[0].click();", element)

2

Andersson 7 年前

只有向下滚动页面时,实际需要的链接才可见。

尝试使用此代码单击链接:

configuration_start = chrome_driver.find_element_by_xpath('//a[@title="Konfiguration starten"]')
chrome_driver.execute_script('arguments[0].scrollIntoView();', configuration_start)    
configuration_start.click()

由于导航面板的位置固定,它可能会与目标链接重叠,因此您可以在处理链接之前更改导航面板样式:

nav_panel = chrome_driver.find_element_by_xpath('//div[@data-module="main-navigation"]')
driver.execute_script('arguments[0].style.position = "absolute";', nav_panel)