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java DataOutputStream异常

dataoutputstream exception java

1

Mr_and_Mrs_D · 技术社区 · 16 年前

import java.io.*;
import java.net.*;

class TCPclient {
    public static void main(String[] args) throws Exception {
        String hostname, msg;
        InetAddress hostaddress;
        BufferedReader inFromUser = new BufferedReader (new InputStreamReader(System.in));
        System.out.println("Please type host\n");
        hostname = inFromUser.readLine();   //I type localhost
        hostaddress = InetAddress.getByName(hostname);
        Socket cSocket = new Socket(hostaddress, 44444);
        String cAddress = cSocket.getLocalSocketAddress().toString();
        DataOutputStream outToServer = new DataOutputStream (cSocket.getOutputStream());
        while (true)
        {
            msg = inFromUser.readLine();
            System.out.println(msg);
            if (msg.equals("exit"))
            {
                System.out.println("exit");
                break;
            }
            outToServer.writeBytes(cAddress + " said : " + msg + '\n'); //this line throws an exception the second time it runs
        }
        cSocket.close();
    }
}

我是java新手,所以我想我遗漏了一些明显的东西。异常读取:

java.net.SocketException:软件错误位于java.net.SocketOutputStream.socketWrite0(本机方法) 在java.net.SocketOutputStream.socketWrite(SocketOutputStream。java:92) 在java.io.DataOutputStream.writeBytes(DataOutputStream。java:259) 在TCPclient.main(TCPclient。java:52)爪哇

服务器:

import java.io.*;
import java.net.*;

class TCPServer {
   public static void main(String argv[]) throws Exception {
      String clientSentence;
      ServerSocket welcomeSocket = new ServerSocket(44444);
      while(true) {
         Socket connectionSocket = welcomeSocket.accept();
         BufferedReader inFromClient = new BufferedReader(
                new InputStreamReader(connectionSocket.getInputStream( ) ) );
         clientSentence = inFromClient.readLine();
         System.out.println(clientSentence + "\n");
      }
   }
}

3 回复 | 直到 14 年前

1

4

Mark Peters 16 年前

您的客户机创建一个套接字,并一遍又一遍地写入该套接字。另一方面,服务器执行以下操作:

ServerSocket welcomeSocket = new ServerSocket(44444);
while(true) {
   Socket connectionSocket = welcomeSocket.accept();

所以要解决眼前的问题,试着搬家

    Socket connectionSocket = welcomeSocket.accept();
    BufferedReader inFromClient = new BufferedReader(
            new InputStreamReader(connectionSocket.getInputStream( ) ) );

2

1

Georgy Bolyuba 16 年前

在打第二行之前你要等多久?这可能与套接字空闲有关。

同样使用这样的服务器代码,您将只看到第一条消息。试试这个:

import java.io.*;
import java.net.*;

class TCPServer {
    public static void main(String argv[]) throws Exception {
        String clientSentence;
        ServerSocket welcomeSocket = new ServerSocket(44444);
        Socket connectionSocket = welcomeSocket.accept();
        BufferedReader inFromClient = new BufferedReader(new InputStreamReader(connectionSocket.getInputStream()));
        while (true) {
            clientSentence = inFromClient.readLine();
            System.out.println(clientSentence + "\n");
        }
    }
}

3

0

Justian Meyer 16 年前

尝试:

while (true)
{
    if(inFromUser.readLine() != null)
    {        
        msg = inFromUser.readLine();

        System.out.println(msg);
        if (msg.equals("exit"))
        {
           System.out.println("exit");
           break;
        }

        outToServer.writeBytes(cAddress + " said : " + msg + "\n");
    }
}

注意这些变化:

if(inFromUser.readLine() != null)
{

... "\n");

不

... '\n');

试试看。这可能是一个太简单的解决方案,但它的东西:)