在(字符串)(Postgresql)中搜索假日doy

这项工作:

WITH month AS ( 
SELECT date_part('doy',d.dt) as doy,
dt::date as date
FROM generate_series('2017-01-01','2017-01-15', interval '1 day') as d(dt)
) 

SELECT date, 
CASE
WHEN doy IN (1,2,3) THEN 0 ELSE 8 END
FROM month

http://sqlfiddle.com/#!15/aed15/10

但是如果我将1,2,3存储为字符串

CREATE TABLE holidays
   (id int4,days character(60));       
INSERT INTO holidays
   (id,days)
VALUES
   ('2017','1,2,3');

...并用该字符串替换1,2,3:

WITH month AS ( 
SELECT date_part('doy',d.dt) as doy, 
dt::date as date
FROM generate_series('2017-01-01','2017-01-15', interval '1 day') as d(dt)
) 

SELECT date, days,
CASE
WHEN doy::text IN (days) THEN 0 ELSE 8 END
FROM month
LEFT JOIN holidays ON id=2017

http://sqlfiddle.com/#!15/aed15/13

“天”似乎是不正确的。但我不知道怎么做。

TIA,