使用jq收集树状json对象中沿每条路径的所有根到叶值

使用jq收集树状json对象中沿每条路径的所有根到叶的值。对于walk或flatten函数来说,这看起来应该很容易,但是尽管已经提出了一些有用的问题,但我还是搞不清楚。

我有这个

 {
     "cond1":["a","b","c"],
     "cond2":["a1","b2","c"],
     "cond2":["a","b","c3"]    
 }    

我想要这个

["cond1","a"]
["cond1","b"]
["cond1","c"]
["cond2","a1"]
["cond2","b2"]
["cond2","c"]
["cond2":"a"]
["cond2":"b"]
["cond2":"c3"]

类似问题: https://github.com/stedolan/jq/issues/646 jq - How do I print a parent value of an object when I am already deep into the object's children?

另外,如果数组不是由[“a”、“b”、“c”]组成的,而是由嵌套对象组成的,那么答案会有什么不同呢,即[“x2”、“x3”]、[“x1”、“x2”]]