python:从对象列表中删除几乎重复的内容

您可以维护一组在迭代时遇到的所有index 1元素,并且只有在没有遇到其index 1元素时,才能在最终结果中包含元组:

lst = [(1051,97),(1051,132),(1048,132),(1048,283),(1048,438)]

s = set()
res = []
for i, j in lst:
    if j not in s:
        s.add(j)
        res.append((i,j))

print(res)
# [(1051, 97), (1051, 132), (1048, 283), (1048, 438)]

lst = [(1051,97),(1051,132),(1048,132),(1048,283),(1048,438)]
lst = list(reversed([(v, k) for k, v in {t[1]: t[0] for t in reversed(lst)}.items()]))
print(lst)
# [(1051, 97), (1051, 132), (1048, 283), (1048, 438)]

使用 pandas

df = pd.DataFrame(l)
df.loc[df[1].drop_duplicates().index].values.tolist()

建立一个反向字典。由于字典键总是唯一的,因此会自然地消除重复:

l = [(1051,97),(1051,132),(1048,132),(1048,283),(1048,438)]
[(x,y) for y,x in {y:x for x,y in l}.items()]
#[(1051, 97), (1048, 132), (1048, 283), (1048, 438)]

这种解决办法不能维持秩序。