让python脚本运行一分钟

这就是答案:

from pynput import keyboard
import threading, time

word_counter = 0

def background():
    def on_press(key):
        global word_counter
        try:
            print('alphabet key {} pressed'.format(key.char))
        except AttributeError:
            if key == keyboard.Key.space:
                word_counter += 1
                print(word_counter)
            elif key == keyboard.Key.esc:
                return False
            print('special key {} pressed'.format(key))

    with keyboard.Listener(on_press=on_press) as listener:
        listener.join()

def wait():
    time.sleep(60)

background = threading.Thread(name = 'background', target = background)
background.start()
wait()

# After a minute, this will be the final output and the program will terminate
print('You typed a total of {} words in a minute'.format(word_counter))

from pynput import keyboard
import time

word_counter = 0


def on_press(key):
    global word_counter
    try:
        print('alphabet key {} pressed'.format(key.char))
    except AttributeError:
        if key == keyboard.Key.space:
            word_counter += 1
            print(word_counter)
        elif key == keyboard.Key.esc:
            return False
        print('special key {} pressed'.format(key))
i=int(time.time())+60
while(time.time()<=i):
     with keyboard.Listener(on_press=on_press) as listener:
          listener.join()

# After a minute, this will be the final output and the program will terminate
print('You typed a total of {} words in a minute'.format(word_counter))

我相信这段代码会运行1分钟。

如:

import time 

i=int(time.time())+60
print("ddnd")
while(int(time.time())<=i):
    print("dlksnd")