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编码和解码跳过字符

  •  1
  • Ullas Hunka  · 技术社区  · 8 年前

    我正在尝试使用编码格式将一些字符串存储到数据库中。但当检索回来时,字符串的格式不正确。

    下面是我的代码示例,您很容易看到传递给encode的字符串与解码后的字符串不同。为什么会这样?

    有没有其他的库可以帮助我编码和解码?任何关于这一点的建议都是有益的。

    var Base64 = {
    	_keyStr : "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",
    	encode : function(e) {
    		var t = "";
    		var n, r, i, s, o, u, a;
    		var f = 0;
    		e = Base64._utf8_encode(e);
    		while (f < e.length) {
    			n = e.charCodeAt(f++);
    			r = e.charCodeAt(f++);
    			i = e.charCodeAt(f++);
    			s = n >> 2;
    			o = (n & 3) << 4 | r >> 4;
    			u = (r & 15) << 2 | i >> 6;
    			a = i & 63;
    			if (isNaN(r)) {
    				u = a = 64
    			} else if (isNaN(i)) {
    				a = 64
    			}
    			t = t + this._keyStr.charAt(s) + this._keyStr.charAt(o)
    					+ this._keyStr.charAt(u) + this._keyStr.charAt(a)
    		}
    		return t
    	},
    	decode : function(e) {
    		var t = "";
    		var n, r, i;
    		var s, o, u, a;
    		var f = 0;
    		e = e.replace(/[^A-Za-z0-9+/=]/g, "");
    		while (f < e.length) {
    			s = this._keyStr.indexOf(e.charAt(f++));
    			o = this._keyStr.indexOf(e.charAt(f++));
    			u = this._keyStr.indexOf(e.charAt(f++));
    			a = this._keyStr.indexOf(e.charAt(f++));
    			n = s << 2 | o >> 4;
    			r = (o & 15) << 4 | u >> 2;
    			i = (u & 3) << 6 | a;
    			t = t + String.fromCharCode(n);
    			if (u != 64) {
    				t = t + String.fromCharCode(r)
    			}
    			if (a != 64) {
    				t = t + String.fromCharCode(i)
    			}
    		}
    		t = Base64._utf8_decode(t);
    		return t
    	},
    	_utf8_encode : function(e) {
    		e = e.replace(/rn/g, "n");
    		var t = "";
    		for (var n = 0; n < e.length; n++) {
    			var r = e.charCodeAt(n);
    			if (r < 128) {
    				t += String.fromCharCode(r)
    			} else if (r > 127 && r < 2048) {
    				t += String.fromCharCode(r >> 6 | 192);
    				t += String.fromCharCode(r & 63 | 128)
    			} else {
    				t += String.fromCharCode(r >> 12 | 224);
    				t += String.fromCharCode(r >> 6 & 63 | 128);
    				t += String.fromCharCode(r & 63 | 128)
    			}
    		}
    		return t
    	},
    	_utf8_decode : function(e) {
    		var t = "";
    		var n = 0;
    		var r = c1 = c2 = 0;
    		while (n < e.length) {
    			r = e.charCodeAt(n);
    			if (r < 128) {
    				t += String.fromCharCode(r);
    				n++
    			} else if (r > 191 && r < 224) {
    				c2 = e.charCodeAt(n + 1);
    				t += String.fromCharCode((r & 31) << 6 | c2 & 63);
    				n += 2
    			} else {
    				c2 = e.charCodeAt(n + 1);
    				c3 = e.charCodeAt(n + 2);
    				t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3
    						& 63);
    				n += 3
    			}
    		}
    		return t
    	}
    }
    
    
    var str = "background:url(/drona-courses/player_assets/skin_0/DRONA_default_skinRightCorner.png) ;"
    
    var encoded = Base64.encode(str);
    //console.log(encoded);
    
    var decoded = Base64.decode(encoded);
    console.log(str,"......Input");
    console.log(decoded,".....Output");
    2 回复  |  直到 8 年前
        1
  •  2
  •   marpme    8 年前
        2
  •  1
  •   Sebastian Olsen    8 年前

    atob btoa

    const foo = "bar"
    
    const encodedFoo = btoa(foo)
    const decodedFoo = atob(encodedFoo)
    
    console.log(encodedFoo)
    console.log(decodedFoo)

    here.

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