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Google Drive API:检查文件夹是否存在

google-drive-api python

0

Brad Solomon · 技术社区 · 7 年前

具体内容:

Python客户端: googleapiclient

给定封闭驱动器ID abcdef ,文件夹名是否为 June 2019 application/vnd.google-apps.folder )存在吗?

当前路线:

>>> from googleapiclient.discovery import build
>>> # ... build credentials
>>> driveservice = build("drive", "v3", credentials=cred).files()
>>> [i for i in driveservice.list().execute()['files'] if 
...  i['name'] == 'June 2019' and i['mimeType'] == 'application/vnd.google-apps.folder']                                                                                                                                                                     
[{'kind': 'drive#file',
  'id': '1P1k5c2...........',
  'name': 'June 2019',
  'mimeType': 'application/vnd.google-apps.folder'}]

所以答案是肯定的,文件夹存在。但应该有更有效的方法 via .list() driveId

>>> FOLDER_ID = "abcdef........"
>>> driveservice.list(corpora="drive", driveId=FOLDER_ID).execute()                                                                                                                                                                                                          
# 403 response, even when adding the additional requested params

我如何使用 q 按文件夹名查询参数?

0 回复 | 直到 7 年前

1

4

Cvetan Mihaylov 7 年前

使用时 driveId corpora="drive" includeItemsFromAllDrives 和 supportsAllDrives

代码:

response = driveservice.list(
    q="name='June 2019' and mimeType='application/vnd.google-apps.folder'",
    driveId='abcdef',
    corpora='drive',
    includeItemsFromAllDrives=True,
    supportsAllDrives=True
).execute()

for item in response.get('files', []):
    # process found item

更新:

如果这是一个驱动器id,您确定它存在,并且您一直收到“Shared drive not found”错误,那么这可能是您为api获取的凭据的作用域问题。另外根据这些Google API文档,似乎发生了很多变化和抨击,都与共享驱动器API支持有关。 https://developers.google.com/drive/api/v3/enable-shareddrives https://developers.google.com/drive/api/v3/reference/files/list

如果您一直有这些问题,这里有一个替代的解决方案供您使用 spaces

response = driveservice.list(
    q="name='June 2019' and mimeType='application/vnd.google-apps.folder'",
    spaces='drive'
).execute()

for item in response.get('files', []):
    # process matched item