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为什么这个javascript函数返回未定义的值?

ecmascript-6 function reactjs javascript

0

Natesh bhat · 技术社区 · 7 年前

let getLowerUpperBoundFromValue=(bound , idToValue)=>{
        // Returns the value of the variable previously generated if "value" is a variable name  or return "value" if its a number . 
        // bound :  can be a direct integer or a variable name. 
        // idToValue : contains the id to value mapping which must contain a variable whose name must be equal to 'bound' parameter if its a variable name . 

        if(isNaN(Number(bound)))
        {
            Object.entries(idToVarStatesGlobal).forEach(idStatePair=>{
                let id= idStatePair[0] , varState = idStatePair[1] ; 
                if(varState.name===bound){
                    console.log("check now Returning idTovalue[id]" , idToValue , id , idToValue[id] , Number(idToValue[id]));
                    return Number(idToValue[id]) ; 
                }
            })
        }
        else return Number(bound); 
    }

console.log('check now: ' , getLowerUpperBoundFromValue(varState.lowerbound , idToValue)) ;

我得到的日志输出如下:

check now Returning idTovalue[id] {PSfCL5hBm: 69} PSfCL5hBm 69 69
inputGeneration.js:99 check now:  undefined

为什么函数返回未定义,即使 Number(idTovalue[id]) 评估为正常值69?

1 回复 | 直到 7 年前

1

2

Smarticles101 7 年前

没有返回任何内容,因为forEach回调是一个单独的方法。我取消了对他的呼叫 .forEach 并用一个 for of 循环,用于维护 return

let getLowerUpperBoundFromValue=(bound , idToValue)=>{
        // Returns the value of the variable previously generated if "value" is a variable name  or return "value" if its a number . 
        // bound :  can be a direct integer or a variable name. 
        // idToValue : contains the id to value mapping which must contain a variable whose name must be equal to 'bound' parameter if its a variable name . 

        if(isNaN(Number(bound)))
        {
            for (let idStatePair of Object.entries(idToVarStatesGlobal)) {
                let id= idStatePair[0] , varState = idStatePair[1] ; 
                if(varState.name===bound){
                    console.log("check now Returning idTovalue[id]" , idToValue , id , idToValue[id] , Number(idToValue[id]));
                    return Number(idToValue[id]) ; 
                }
            }
        }
        else return Number(bound); 
    }