我有一份清单
List<Payment>
List<PaymentPlan>
. 这些类型如下所示:
public class Payment {
@XmlElement(name = "Installment")
@JsonProperty("Installment")
private List<Installment> installments = new ArrayList<>();
@XmlElement(name = "OriginalAmount")
@JsonProperty("OriginalAmount")
private BigDecimal originalAmount;
//getters setters, more attributes
}
和
public class PaymentPlan {
//(Installment in different package)
private List<Installment> installments;
@XmlElement(name = "OriginalAmount")
@JsonProperty("OriginalAmount")
private BigDecimal originalAmount;
//getters setters, more attributes
}
我希望这样的事情能奏效。。。
@Mappings({
@Mapping(//other mappings...),
@Mapping(source = "payments", target = "paymentInformation.paymentPlans")
})
ResultResponse originalResponseToResultResponse(OrigResponse originalResponse);
...但我得到:
Can't map property java.util.List<Payment> to java.util.List<PaymentPlan>.
Consider to declare/implement a mapping method java.util.List<PaymentPlan> map(java.util.List<Payment> value);
我不知道如何应用这些信息。首先,我认为我需要为列表声明一些额外的映射(在同一个映射器类中),因此MapStruct知道如何映射列表类型的每个字段,如下所示:
@Mappings({
@Mapping(source = "payment.originalAmount", target = "paymentInformation.paymentPlan.originalAmount")
})
List<PaymentPlan> paymentToPaymentPlan(List<Payment> payment);
...但我收到的错误消息如下
The type of parameter "payment" has no property named "originalAmount".
显然,我做了一些完全错误的事情,因为听起来它甚至无法识别列表的类型。
@Mapping(target = "paymentPlans",expression="java(Helper.mapManually(payments))")
