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如何在gtk.TextBuffer中等待用户输入暂停?

pygtk gtk python

simon ArrowInTree · 技术社区 · 16 年前

我已经考虑过使用 threading.Timer ,每次发出“已更改”信号时,取消并重新启动计时器以调用更新功能。我也尝试过使用 gtk.idle_add() ,但我似乎无法让它工作。

下面是一个非常简单的例子——有人能提出实现我追求的目标的最佳策略吗,最好举个例子?

import gtk

class example:
    def __init__(self):
        window = gtk.Window()
        window.set_title("example")
        window.resize(600,400)
        box = gtk.HBox(homogeneous = True, spacing = 2)
        buf = gtk.TextBuffer()
        buf.connect("changed", self.buf_on_change)
        textInput = gtk.TextView(buf)
        box.add(textInput)
        self.lbl = gtk.Label()
        box.add(self.lbl)
        window.add(box)
        window.connect("destroy", gtk.main_quit)
        window.show_all()

    def buf_on_change(self, buf):
        txt = buf.get_text(*buf.get_bounds())
        output = self.renderText(txt)
        self.lbl.set_text(output)

    def renderText(self, txt):
        # perform computation-intensive text-manipulation here
        output = txt
        return output

if __name__ == '__main__':
    example()
    gtk.main()

2 回复 | 直到 16 年前

simon ArrowInTree 16 年前

glib.timeout_add() 而不是 threading.Timer :

import gtk, glib

class example:
    def __init__(self):
        window = gtk.Window()
        window.set_title("example")
        window.resize(600,400)
        box = gtk.HBox(homogeneous = True, spacing = 2)
        self.buf = gtk.TextBuffer()
        self.buf.connect("changed", self.buf_on_change)
        textInput = gtk.TextView(self.buf)
        box.add(textInput)
        self.lbl = gtk.Label()
        box.add(self.lbl)
        window.add(box)
        window.connect("destroy", gtk.main_quit)
        window.show_all()

        self.timer = glib.timeout_add(1000, self.renderText)

    def buf_on_change(self, buf):
        glib.source_remove(self.timer)
        self.timer = glib.timeout_add(1000, self.renderText)


    def renderText(self):
        txt = self.buf.get_text(*self.buf.get_bounds())
        # perform computation-intensive text-manipulation here
        self.lbl.set_text(txt)
        return False

if __name__ == '__main__':
    example()
    gtk.main()

这似乎可以按预期工作,但因为我对gtk(以及一般的桌面dui编程——以防您不知道;)是完全陌生的)我想留下这个问题,希望有更多经验的人能够对实现这种效果的最佳方式发表意见。我希望没问题吧?

snies 16 年前

import termios, fcntl, sys, os, time, threading
fd = sys.stdin.fileno()

#just setting up the terminal input
oldterm = termios.tcgetattr(fd)
newattr = termios.tcgetattr(fd)
newattr[3] = newattr[3] & ~termios.ICANON & ~termios.ECHO
termios.tcsetattr(fd, termios.TCSANOW, newattr)
oldflags = fcntl.fcntl(fd, fcntl.F_GETFL)
fcntl.fcntl(fd, fcntl.F_SETFL, oldflags | os.O_NONBLOCK)


class example:
  def __init__(self, timeout):
    self.timeout = timeout
    self.timer = threading.Timer(timeout, self.render_text)
    self.txt = ''
    self.timer.start() #at the end of __init__ 

  def buf_on_change(self, buf):
    print "Got buffer:", buf, time.ctime()
    self.txt = self.txt + buf
    self.timer.cancel()   #won't do no harm if timer already elapsed
    self.timer = threading.Timer(self.timeout, self.render_text)
    self.timer.start()

  def render_text(self):
    print "starting intensive computation"
    print "rendering", self.txt
    time.sleep(3)
    print "stopping intensive computation"


# just my poor mans event loop for the text input
obj = example(3)
try:
    while 1:
        time.sleep(0.001) #just to keep processor cool
        try:
            buf = sys.stdin.read(5)
            obj.buf_on_change(buf)
        except IOError: pass
finally:
    termios.tcsetattr(fd, termios.TCSAFLUSH, oldterm)
    fcntl.fcntl(fd, fcntl.F_SETFL, oldflags)