从文件中删除逗号

忽略一个字节等于一个字符的假设,并且假设文件末尾没有换行符,并且您希望保留空间,那么应该可以这样做:

with open('data.txt', 'ab'):
    f.seek(-1, 2)
    f.truncate()

使用此:

res = your_string.rstrip(',')

documentation

希望有帮助 感谢

这个怎么样。

rf = open('data.txt').read()
with open('data.txt', 'w') as wf:
    wf.write(rf[:-3])

我注意到了 , 不是数据中的最后一个符号,这就是为什么您的解决方案以及 rstrip(',') 不起作用。使用 replace 取而代之的是:

with open('data.txt', 'r') as f:
    data = f.read().replace('} ,', '}')

with open('data.txt', 'w') as f:
    f.write(data)

此脚本只删除最后一个逗号(自 '} ,' 只在每行末尾出现),您将在输出上得到以下信息:

{"time":"2019-02-12T14:41:25.2424552+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Alteraciones_Primitivas_dmz_","service":"GetAlteracion","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_85531"},"response":null,"status":200}
{"time":"2019-02-12T14:41:25.5525828+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Expedientes_dmz_","service":"GetObligatoriedadDocumental","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_85531","tipo_alteracion":"ALT_1","id_expediente":""},"response":null,"status":400}
{"time":"2019-02-12T14:41:25.9169746+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Alteraciones_Primitivas_dmz_","service":"Ubicar","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_85531","epsg":"EPSG:4326"},"response":null,"status":200}
{"time":"2019-02-12T14:41:29.8222248+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Alteraciones_Primitivas_dmz_","service":"GetAlteracion","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_17819"},"response":null,"status":200}
{"time":"2019-02-12T14:41:29.9708861+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Expedientes_dmz_","service":"GetObligatoriedadDocumental","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_17819","tipo_alteracion":"ALT_1","id_expediente":""},"response":null,"status":400}
{"time":"2019-02-12T14:41:30.3077709+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Alteraciones_Primitivas_dmz_","service":"Ubicar","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_17819","epsg":"EPSG:4326"},"response":null,"status":200}
{"time":"2019-02-12T14:41:38.7145697+01:00","ip":"::1","browser":"Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.96 Safari/537.36","user":"28969523B","profile":"SUMUM_D?99?2017?2","controller":"Documentos_dmz_","service":"obtenerDocumento","delegacion":null,"municipio":null,"method":"GET","parameters":{"id_alteracion":"11_31_17819","documento":"E000226847","control":11},"response":null,"status":200}

此解决方案定位最后一个 } 在最后一行中,将字符串替换为索引。

以后可以选择重命名“new”文件。

with open("datain.txt", 'r') as f_in, open('dataout.txt', 'w') as f_out:
    last = None
    for l in f_in.readlines():
        if last:
            f_out.write(last)
        last = l
    i = last.rfind("}")
    f_out.write(last[:i+1])

您也可以这样做,但是我不知道它如何处理编码,而且循环可能会受到更多限制,因此您不会最终截断整个文件。

import os
with open("datain.txt", "r+") as f:
    f.seek(0, os.SEEK_END)
    pos = f.tell()

    while pos > 0:
        f.seek(pos)
        c = f.read(1).encode('utf-8')
        if c == b'}':
            break
        pos = f.tell() - 2
    f.truncate(pos)