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AQL-在ArangoDB中查找具有非唯一属性的文档

aql arangodb

3

Elias Strehle · 技术社区 · 8 年前

假设我有以下文件:

{"_key": "1", "name": "George Washington"}
{"_key": "2", "name": "George Washington"}
{"_key": "3", "name": "John Adams"}
{"_key": "4", "name": "Thomas Jefferson"}
{"_key": "5", "name": "George Washington"}
{"_key": "6", "name": "Thomas Jefferson"}

我想写一个AQL语句,返回按名称分组的文档的键,

[["1", "2", "5"], ["4", "6"]]

到目前为止,我已经想出了

FOR doc IN documents
    LET key = doc._key
    COLLECT name = doc.name INTO groups KEEP key
    RETURN (FOR g IN groups RETURN g["key"])

这将返回:

[["1", "2", "5"], ["3"], ["4", "6"]]

如何修改AQL命令以仅获取具有两个或多个条目的数组?

2 回复 | 直到 8 年前

1

stj 8 年前

FOR doc IN documents
  LET key = doc._key     
  COLLECT name = doc.name INTO groups KEEP key 
  LET keys = groups[*].key 
  FILTER LENGTH(keys) > 1 
  RETURN keys

2

0

Elias Strehle 8 年前

解决了它:

FOR doc IN documents
    LET key = doc._key
    COLLECT name = doc.name INTO groups KEEP key
    LET groups2 = (FOR group IN groups RETURN group["key"])
    FILTER LENGTH(groups2) >= 2
    RETURN groups2