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如何从每个段落中仅选择一个复选框?

checkbox jquery-ui html jquery javascript

Rishi Jagati · 技术社区 · 8 年前

使用的HTML

 <div class="firstrow"><div class="srno"><p>1.</p></div><div class="survey"><span>I am satisfied with the quality, reliability and speed of the computer I use.</span></div></div>
    <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
<div class="firstrow"><div class="srno"><p>2.</p></div><div class="survey"><span>The Software currently installed on my computer is adequate for my job function.</span></div></div>
   <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>

如何使用jquery实现这一点,我已经尝试了很多,但在只有一个调查问题的情况下取得了成功。当我选中另一个问题复选框时,这将删除以前选中的问题复选框。

使用的Jquery

$(function () {
   $('input:checkbox').click(function () {
      if ($(this).is(':checked')) {
          $('input:checkbox').not(this).prop('checked', false);
       }
   });
})

5 回复 | 直到 5 年前

Death-is-the-real-truth 8 年前

注:- 实际上,最好使用单选按钮,然后不需要jQuery。

但如果您想使用复选框和jQuery,请执行以下操作:-

$(function () {
   $('input:checkbox').click(function () {
      if ($(this).is(':checked')) {
          $(this).parent().siblings().children("input:checkbox").prop('checked', false);
       }
   });
})

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="firstrow"><div class="srno"><p>1.</p></div><div class="survey"><span>I am satisfied with the quality, reliability and speed of the computer I use.</span></div></div>
    <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
<div class="firstrow"><div class="srno"><p>2.</p></div><div class="survey"><span>The Software currently installed on my computer is adequate for my job function.</span></div></div>
   <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>

Mayank Pandeyz 8 年前

在多个选项中仅选择一个选项,而不是使用 checkbox 使用 radio 并为属于同一类别的所有收音机赋予相同的名称,以便一次只能检查一个收音机。

<p>Topic 1
  <input type="radio" name="topic1">One
  <input type="radio" name="topic1">Two
</p>

<p>Topic 2
  <input type="radio" name="topic2">One
  <input type="radio" name="topic2">Two
</p>

Sergej 8 年前

使用 <input type="radio" /> 而不是 <input type="checkbox" />

.siblings() 而不是 .not(this)

Chandra Kumar 8 年前

尝试此代码工作:

演示: https://output.jsbin.com/ketunanizo

https://jsbin.com/ketunanizo/edit?html,js,output

HTML:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JS Bin</title>
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
</head>
<body>
<div class="firstrow"><div class="srno"><p>1.</p></div><div class="survey"><span>I am satisfied with the quality, reliability and speed of the computer I use.</span></div></div>
    <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
<div class="firstrow"><div class="srno"><p>2.</p></div><div class="survey"><span>The Software currently installed on my computer is adequate for my job function.</span></div></div>
   <div class="options">
        <span class="optpadding"><input type="checkbox" name="Strongly agree" value="Strongly agree"><span>Strongly agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Agree" value="Agree"><span>Agree</span></span>
        <span class="optpadding"><input type="checkbox" name="Disagree" value="Disagree"><span>Disagree</span></span>
        <span class="optpadding"><input type="checkbox" name="Strongly disagree" value="Strongly disagree"><span>Strongly disagree</span></span>
    </div>
</body>
</html>

<script>
$(function () {
   $('input:checkbox').click(function () {
      if ($(this).is(':checked')) {
          $(this).closest('.options').find('input:checkbox').not(this).prop('checked', false);
       }
   });
})
</script>

Manoprabu R 8 年前

试试这个,它肯定会奏效。。。。

$('input:checkbox').click(function () {
  if ($(this).is(':checked')) {
      $(this).parent().siblings().children().prop('checked', false);
   }
});