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如何使用Prophesy在Zend Expressive中对RequestHandlerInterface类进行双重测试?

prophecy zend-expressive unit-testing

1

Knight · 技术社区 · 8 年前

我想做一个单元测试 process() Zend表示应用程序中中间件的方法。要做到这一点,我需要模仿 $delegate 类型为的方法的参数 RequestHandlerInterface 会有办法的 handle() .

这应该很容易做到,因为我在这个测试中成功地用Prophesy对其他对象进行了模拟:

每当 句柄() 方法被调用时,我收到以下错误: "Unexpected method call on Double\RequestHandlerInterface\P18:\n - handle(\n Double\ServerRequestInterface\P17:000000004a01de0d000000000617c05e Object (\n 'objectProphecy' => Prophecy\Prophecy\ObjectProphecy Object (*Prophecy*)\n )\n )\nexpected calls were:\n - handle(\n\n )"

句柄() 上的方法 $mockDelegate 调用时仍抛出错误:

/**
 * @test
 */
public function 
testReturnsRedirectResponseForHandlerWhenNoErrorsFoundRequestTypePOST()
{

    $renderer = $this->prophesize(TemplateRendererInterface::class);
    $renderer
        ->render('app::contract-form-page', [])
        ->willReturn('');

    $validateSubmitAction = new ValidateSubmitAction(
        $this->router->reveal(),
        $renderer->reveal(),
        get_class($this->container->reveal()),
        $this->logger->reveal()
    );

    $mockRequest = $this->prophesize(ServerRequestInterface::class);
    $mockRequest->getMethod()->willReturn('POST');
    $mockRequest->getBody()->willReturn(
    //create fake object with getContents method
        new class {
            public function getContents(){ return 'location-number=testLoc&contract-number=1234';}
        });

    $mockDelegate = $this->prophesize(RequestHandlerInterface::class);
    $mockDelegate->handle()->willReturn('');

    $response = $validateSubmitAction->process(
        $mockRequest->reveal(),
        $mockDelegate->reveal()
    );

    $this->assertInstanceOf(ValidateSubmitAction::class, $validateSubmitAction);
}

public function process(ServerRequestInterface $request, RequestHandlerInterface $delegate): ResponseInterface
{
    ...
    // Delegate on to the handler
    return $delegate->handle($request); //<-- this is where the error occurs in the unit test

我怎样才能准确地模仿 RequestHandlerInterface handle() 用Prophesy方法来实现一个无错误的测试?

1 回复 | 直到 8 年前

1

2

xtreamwayz 8 年前

你有这个: $mockDelegate->handle()->willReturn('');

$handler->handle(Argument::that([$mockRequest, 'reveal']))->willReturn('');

在代码中,您希望handle()在没有任何参数的情况下被调用。但它是用模拟请求接口的实例调用的。

zend-expressive-session :

public function testMiddlewareCreatesLazySessionAndPassesItToDelegateAndPersistsSessionInResponse()
{
    $request = $this->prophesize(ServerRequestInterface::class);
    $request
        ->withAttribute(SessionMiddleware::SESSION_ATTRIBUTE, Argument::type(LazySession::class))
        ->will([$request, 'reveal']);

    $response = $this->prophesize(ResponseInterface::class);

    $handler = $this->prophesize(RequestHandlerInterface::class);
    $handler->handle(Argument::that([$request, 'reveal']))->will([$response, 'reveal']);

    $persistence = $this->prophesize(SessionPersistenceInterface::class);
    $persistence
        ->persistSession(
            Argument::that(function ($session) use ($persistence, $request) {
                $this->assertInstanceOf(LazySession::class, $session);
                $this->assertAttributeSame($persistence->reveal(), 'persistence', $session);
                $this->assertAttributeSame($request->reveal(), 'request', $session);
                return $session;
            }),
            Argument::that([$response, 'reveal'])
        )
        ->will([$response, 'reveal']);

    $middleware = new SessionMiddleware($persistence->reveal());
    $this->assertSame($response->reveal(), $middleware->process($request->reveal(), $handler->reveal()));
}