当数值字符串值超过“9999”时,将其重置为“1”

使用模运算符:

String currentNumber = "9999";

String incremented = String.format("%0" + currentNumber.length() + "d",
                (Integer.parseInt(currentNumber) + 1) % 9999);

当你用合适的打字机打电话时,应该是这样的 currentNumber :

Integer currentNumber = 9999;
Integer moduledNumber = (currentNumber + 1) % 9999;
String incremented = String.format("%0" + currentNumber.toString().length() + "d", moduledNumber);

您可以为此创建自定义方法

String increment(String num,int incrementBy) //incrementBy  is an integer by which you want to increment
{  
    int numInt=Integer.parseInt(num);
    numInt+=incrementBy;
    if (numInt>9999)
        return String.valueOf(numInt%9999);
    return String.valueOf(numInt);
}

为什么不用if语句?

if (Integer.parseInt(currentNumber) > Integer.parseInt(maxNumber))
currentNumber = "0001"

希望对你有帮助