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twilio/python/flask:向前呼叫,如果没有及时应答,则重定向到语音邮件

twilio flask python-3.x

0

HippoMan · 技术社区 · 7 年前

我已经编写了一个flask应用程序(使用python3),我已经在twilio注册了这个应用程序,以响应twilio提供的电话号码的来电。我可以让它路由到语音邮件,挂断,忽略呼叫,并转发到另一个电话号码,我在这里呼叫 target

但有一项功能我还没有弄清楚如何在这个框架内实现 twilio python / flask 应用程序。如果传入号码没有被我的应用程序逻辑拒绝,我希望呼叫被转发到目标号码。但是,如果在30秒内没有人接这个号码,我希望电话能转到我通过的语音信箱 twimlets . 我不知道如何在这里实现这个条件转发/语音邮件逻辑。

这必须发生在 answer_call 以下代码底部附近的方法:

import re

from flask import Flask, Response, redirect, request, send_file
from twilio.twiml.voice_response import VoiceResponse

app = Flask(__name__)

ngrokurl = 'http://XXXXXXXX.ngrok.io'
vmbase   = 'http://twimlets.com/voicemail?Email=USER@DOMAIN.COM&Transcribe=False'
vmpath   = '/path/to/voicemessage.mp3'
vmurl    = os.path.join(ngrokurl, 'vm')
fwd      = '+1-111-111-11111'

def num(n):
    return re.compile(n)

whitelist = [
    num(r'^[+]11100000000$'),
    num(r'^[+]11111100000$'),
    num(r'^[+]11111111100$'),
]

ignorelist = [
    num(r'^[+]2000'),
]

hanguplist = [
    num(r'^[+]3000'),
]

def number_in(n, numlist):
    if not n or not numlist:
        return False
    for item in numlist:
        if item.search(n):
            return True
    return False

def voicemail():
    return redirect(
        '{}&Message={}'.format(vmbase, vmurl),
        302
    )

def ignore():
    resp = VoiceResponse()
    resp.play(vmurl, loop=1)
    return Response(str(resp), 200, mimetype='application/xml')

def hangup():
    resp = VoiceResponse()
    resp.hangup()
    return Response(str(resp), 200, mimetype='application/xml')

def forward():
    resp = VoiceResponse()
    resp.dial(fwd)
    return Response(str(resp), 200, mimetype='application/xml')

@app.route('/answer', methods=['GET', 'POST'])
def answer_call():
    '''
    Main flask route for answering phone calls.
    '''
    number = request.args.get('From', None)
    if not number:
        return hangup()
    if number_in(number, whitelist):
        # Whitelisted numbers are directly forwarded.
        #
        # However, what I want to do here is forward to
        # the target number, but then to redirect
        # to voicemail if the call isn't answered
        # after, say, 30 seconds. Don't know how ... ???
        #
        return forward()
##        return voicemail()
    elif number_in(number, ignorelist):
        return ignore()
    elif number_in(number, hanguplist):
        return hangup()
    else:
        #
        # Same question here: how do I forward
        # to the target but then redirect
        # to voicemail if the call isn't answered?
        #
        return forward()
##        return voicemail()

@app.route('/vm', methods=['GET', 'POST'])
def vm():
    '''
    URL for the voicemail recording used within the
    twimlets voicemail call. See `vmurl`, above.
    '''
    return send_file(vmpath, 'audio/mpeg')

if __name__ == "__main__":
    app.run(debug=True)

提前感谢你们的指点和建议。

2 回复 | 直到 7 年前

1

2

Alan 7 年前

应该为forward()函数的谓词定义一个动作URL。然后,请求到该操作URL的DialCallStatus(它将引导回Flask应用程序的URL)将告诉您调用是否成功。如果调用未成功“完成”,则将路由到VM逻辑,否则。一个动词的默认超时时间是30秒,所以你在那里很好。

关键逻辑在下面的函数中,将逻辑移植到Python应该没有那么困难。

在函数中创建语音邮件操作 https://www.twilio.com/docs/wireless/tutorials/communications-guides/implement-voicemail#create-voicemail-action-in-functions

因此,基本上对于上述函数,如果DialCallStatus完成,您希望挂断呼叫,否则将路由到VM/Twimlet。

2

0

HippoMan 7 年前

forward 和 answer_call 从我最初的例子,它添加了一个新的 call_result

现在,REST-ful应用程序将列出已批准的号码并阻止不需要的号码。任何已批准或未阻止的号码都将转发到目标电话号码。如果20秒后无人接听,应用程序会将呼叫路由到我的手机 twimlet

显然,这个示例应用程序包含硬编码的过滤器,这些过滤器只包含伪数据。在现实生活中,每次有调用传入时,我都会从数据存储中加载这些。这样,我就可以从REST-ful应用程序外部修改这些过滤器,而不必重新编译甚至重新启动该应用程序。

到目前为止,我的初始编码工作得很好。

def forward():
    resp = VoiceResponse()
    resp.dial(
        fwd,
        action=url_for('call_result'),
        method='GET',
        timeout=20
    )
    return Response(str(resp), 200, mimetype='application/xml')

@app.route('/answer', methods=['GET', 'POST'])
def answer_call():
    number = request.args.get('From', None)
    if not number:
        return hangup()
    elif number_in(number, whitelist):
        return forward()
    elif number_in(number, ignorelist):
        return ignore()
    elif number_in(number, hanguplist):
        return hangup()
    else:
        return forward()

@app.route('/call', methods=['GET', 'POST'])
def call_result():
    status = request.args.get('DialCallStatus', None)
    if not status or status != 'completed':
        return voicemail()
    else:
        return Response(str(resp), 200, mimetype='application/xml')