uuid.UUID
:
import uuid
import sqlalchemy
foreign_uuid = '822965bb-c67e-47ee-ad12-a3b060ef79ae'
qry = Query(MyModel).filter(MyOtherModel.uuid == uuid.UUID(foreign_uuid))
现在我想从SQLAlchemy获取原始postgresql:
qry.statement.compile(dialect=postgresql.dialect(), compile_kwargs={"literal_binds": True}))
这会产生以下错误:
NotImplementedError: Don't know how to literal-quote value UUID('822965bb-c67e-47ee-ad12-a3b060ef79ae')
这似乎是因为SqlAlchemy只知道如何处理基本类型。
The documentation suggests
TypeDecorator
甚至还为guid提供了一个:
from sqlalchemy.dialects.postgresql import UUID
import uuid
class GUID(TypeDecorator):
"""Platform-independent GUID type.
Uses PostgreSQL's UUID type, otherwise uses
CHAR(32), storing as stringified hex values.
"""
impl = CHAR
def load_dialect_impl(self, dialect):
if dialect.name == 'postgresql':
return dialect.type_descriptor(UUID())
else:
return dialect.type_descriptor(CHAR(32))
def process_bind_param(self, value, dialect):
if value is None:
return value
elif dialect.name == 'postgresql':
return str(value)
else:
if not isinstance(value, uuid.UUID):
return "%.32x" % uuid.UUID(value).int
else:
# hexstring
return "%.32x" % value.int
def process_result_value(self, value, dialect):
if value is None:
return value
else:
if not isinstance(value, uuid.UUID):
value = uuid.UUID(value)
return value
但是它没有说怎么做
使用
打字机
. 我需要在我的模型中引用它吗?我能把它提供给
.statement.compile
打电话?