从字符串转换为双精度未能按预期转换

我正在尝试将“21898.99”转换为字符串,但继续得到21898.99000000002,但我期望得到21898.99

#include <cstdlib>
#include <boost/lexical_cast.hpp>
#include <limits>
#include <iostream>
int main()
{
    double d1 = std::strtod("21898.99", nullptr);
    long double d2 = std::strtold("21898.99", nullptr);
    float d3 = std::strtof("21898.99", nullptr);

    double d4 = atof("21898.99");

    double d5 = boost::lexical_cast<double>("21898.99");

    double d6;  
    sscanf_s("21898.99", "%lf", &d6);

    double d7;
    sscanf_s("21898.99", "%lg", &d7);

    std::istringstream ss("21898.99");
    double d8 = 0.0;
    ss >> d8;

    typedef std::numeric_limits< double > dbl;
    std::cout.precision(dbl::max_digits10);
    std::cout << d1 << "\n";
    std::cout << d2 << "\n";
    std::cout << d3 << "\n";
    std::cout << d4 << "\n";
    std::cout << d5 << "\n";
    std::cout << d6 << "\n";
    std::cout << d7 << "\n";
    std::cout << d8 << "\n"; 
}

21898.990000000002
21898.990000000002
21898.990234375
21898.990000000002
21898.990000000002
21898.990000000002
21898.990000000002
21898.990000000002

Windows 10版本10.0.14939.0

Windows SDK 10.0.17134.0

我用gcc在centos机器上进行了尝试,这个调用有效,但其他调用也失败了。
长双d2=std::strtold(“21898.99”,空PTR); 因为它返回21898.99