通过类装饰器自动将类添加到列表中?

有可能在装饰器中获得“类对象”(构造函数)的句柄吗?

"@date:2019-01-25" "@latlong:51.507351,-0127758"

装饰器看起来很有前途,至少我可以将标记定义为类属性:

function dkdatatype({tag}) {
    return function decorator(cls) {
        if (cls.kind !== 'class') throw `not class ${cls.kind}`;

        cls.elements.push({
            kind: 'field',
            key: 'tag',
            placement: 'static', 
            descriptor: {
                configurable: false,
                enumerable: true,
                writable: false
            },
            initializer: () => tag
        });

        return {
            kind: 'class',
            elements: cls.elements
        };
    };
}

@dkdatatype({tag: '@date:'})
export class DkDate extends datatype {
    constructor(...args) {
        super();
        const clstag = this.constructor.tag;
        if (typeof args[0] === 'string' && args[0].startsWith(clstag)) {
            this.value = new Date(args[0].substr(clstag.length));
        } else {
            this.value = new Date(...args);
        }
    }
    toJSON() {
        return this.constructor.tag + this.value.toISOString().slice(0, 10);
    }
}

type_registry[DkDate.tag] = DkDate

但是有没有任何方法可以从装饰器(或者基类,或者其他方式)自动(并且只执行一次)执行此操作?