如何检查以下所有项目是否都在列表中?

类似于 <= 在Python中,通常不会重写为表示与“小于或等于”明显不同的内容。标准库这样做是不寻常的——对我来说,它闻起来像是遗留的API。

set.issubset . 请注意,您不需要将参数转换为集合;如果需要,它将为您这样做。

set(['a', 'b']).issubset(['a', 'b', 'c'])

我可能会用 set 以如下方式:

set(l).issuperset(set(['a','b'])) 

set(['a','b']).issubset(set(l)) 

我喜欢这两个,因为它们看起来最符合逻辑,后者更短,可能更快(这里用 set backported 到Python2.7):

all(x in {'a', 'b', 'c'} for x in ['a', 'b'])
#   or
{'a', 'b'}.issubset({'a', 'b', 'c'})

如果您的列表包含如下重复项:

v1 = ['s', 'h', 'e', 'e', 'p']
v2 = ['s', 's', 'h']

set(v2).issubset(v1)

要计算重复项,可以使用以下代码:

v1 = sorted(v1)
v2 = sorted(v2)


def is_subseq(v2, v1):
    """Check whether v2 is a subsequence of v1."""
    it = iter(v1)
    return all(c in it for c in v2) 

is_subseq(v2, v1)

这就是我在网上搜索的内容,但不幸的是,在python解释器上进行实验时,我发现不是在网上。

>>> case  = "caseCamel"
>>> label = "Case Camel"
>>> list  = ["apple", "banana"]
>>>
>>> (case or label) in list
False
>>> list = ["apple", "caseCamel"]
>>> (case or label) in list
True
>>> (case and label) in list
False
>>> list = ["case", "caseCamel", "Case Camel"]
>>> (case and label) in list
True
>>>

如果你有一个很长的变量列表 sublist variable

>>>
>>> list  = ["case", "caseCamel", "Case Camel"]
>>> label = "Case Camel"
>>> case  = "caseCamel"
>>>
>>> sublist = ["unique banana", "very unique banana"]
>>>
>>> # example for if any (at least one) item contained in superset (or statement)
...
>>> next((True for item in sublist if next((True for x in list if x == item), False)), False)
False
>>>
>>> sublist[0] = label
>>>
>>> next((True for item in sublist if next((True for x in list if x == item), False)), False)
True
>>>
>>> # example for whether a subset (all items) contained in superset (and statement)
...
>>> # a bit of demorgan's law
...
>>> next((False for item in sublist if item not in list), True)
False
>>>
>>> sublist[1] = case
>>>
>>> next((False for item in sublist if item not in list), True)
True
>>>
>>> next((True for item in sublist if next((True for x in list if x == item), False)), False)
True
>>>
>>>

issublist = lambda x, y: 0 in [_ in x for _ in y]

不是OP的情况,但是-对于任何想要在 最后因为谷歌搜索不好(比如我)而来到这里-你需要和 dict.items :

>>> a = {'key': 'value'}
>>> b = {'key': 'value', 'extra_key': 'extra_value'}
>>> all(item in a.items() for item in b.items())
True
>>> all(item in b.items() for item in a.items())
False

那是因为 听写项目 返回键/值对的元组,与Python中的任何对象一样,它们可以互换比较