矩阵数到矩阵ASCII的转换?

是什么 store 在代码中。修复此错误后,它可以正常工作

#!usr/bin/env/python3.6
# imports
import numpy as np
import random
# Generated random matrix of 25 spaces, 
# where placed ramdom number between 0 to 255,
# and store in a variable.
matrix = np.random.randint(33,255, size=(5, 5))

# This shows the matrix of integer numbers.
print(matrix) # Good!!!
# This translate  matrix of number to ASCII table symbols:
for col in range(5):
    for row in range(5):
        print(chr(matrix[row][col]), end=' ')
    print('\n') # Solved, my honey.

输出为-

[[ 86 159  40 221 211]
 [166 224 213 252 160]
 [155 160 111 109 164]
 [ 98 190  34 250  40]
 [115 228  59 139 221]]

V ¦  b s 
 à   ¾ ä 
( Õ o " ; 
Ý ü m ú  
Ó   ¤ ( Ý 

这

dtype = np.uint16 if np.dtype('U1').itemsize==2 else np.uint32
matrix.astype(dtype).view('U1')
array([['Ö', '´', 'O', 'i', '\x98'],
       ['à', 'ü', 'S', 'm', 'æ'],
       ['ý', 'm', '#', 'ö', 'u'],
       ['±', 'l', '\x82', 'O', 'È'],
       ['h', '&', '\x82', 'ª', '\xad']],
      dtype='<U1')

工作类型。但不是百分之百确定它是ASCII码。但它的作用与 chr :

import pprint
>>> pprint.pprint([[chr(number) for number in row] for row in matrix])
[['Ö', '´', 'O', 'i', '\x98'],
 ['à', 'ü', 'S', 'm', 'æ'],
 ['ý', 'm', '#', 'ö', 'u'],
 ['±', 'l', '\x82', 'O', 'È'],
 ['h', '&', '\x82', 'ª', '\xad']]

我们要做的是 uint16 或 uint32 因为 U 数据类型似乎每个字符有2或4个字节。然后,我们观看 U1 将数字重新解释为字符,仅此而已。