从python代码中进行graphQL变异,得到错误

GraphQl提供了一种用JSON发送数据的方法。您可以在查询中使用变量,并将JSON对象作为变量值发送:

def make_query(self, query, variables, url, headers):
    """
    Make query response
    """
    request = request.post(url, json={'query': query, 'variables': variables}, headers=headers)
    if request.status_code == 200:
        return request.json()
    else:
        raise Exception("Query failed to run by returning code of {}. {}".format(request.status_code, query))

查询如下所示:

query = """
    mutation CreateCustomer($input:CustomerInput){
        customerCreate(customerData: $input){
            customer{
                name
            }
        }
    }
"""
variables = {'input': customer}

您还可以使用库,例如 python-graphql-client 要提出相同的请求,请执行以下操作:

client = GraphQLClient('http://127.0.0.1:5000/graphql')

query = """
mutation CreateCustomer($input:CustomerInput){
    customerCreate(customerData: $input){
        customer{
            name
        }
    }
}
"""

variables = {'input': customer}

client.execute(query, variables)

我通过浏览器跟踪了变异请求,并准确复制了发送的json,去掉了换行符。在代码中,我添加了{“query”:json},它起了作用

示例我使用发送2个参数和接收令牌:

mutation = """mutation {  
    login(    username: "myusername",    password: "mypassword",  ) 
        {   
            token 
        }
    }"""
    
res = requests.post(url, json={"query": mutation} )