尝试在PHP中对关联数组排序

做 sort 通过 名称 像这样循环使用 foreach()

<?php

$fonts = array(
    0 => ["index" => 0, "name" => "Arial", "path" => "assets/fonts/arial.ttf"],
    1 => ["index" => 1, "name" => "Times", "path" => "assets/fonts/times.ttf"],
    2 => ["index" => 2, "name" => "Roboto", "path" => "assets/fonts/roboto.ttf"],
    3 => ["index" => 3, "name" => "AlexBrush", "path" => "assets/fonts/AlexBrush-Regular.ttf"],
);

uasort($fonts, function($a, $b) {
    return strcmp($a['name'], $b['name']);
});

print_r($fonts);

foreach($fonts as $font){
 echo $font["name"].PHP_EOL;
}

?>

编辑:

 $indexed_array = array_column($fonts,'name','index'); // array column map name by index
 print_r($indexed_array); 
 echo $indexed_array[3];

演示: https://3v4l.org/W7BOH

当你使用。。。

for($i = 0; $i < 4; $i++)
{
    echo "<br/>".$fonts[$i]["name"];
}

要打印出这些值,可以按数字顺序使用索引来显示它们。

如果你用。。。

print_r($fonts);

你会看到他们已经被分类并得到。。。

Array
(
    [3] => Array
        (
            [index] => 3
            [name] => AlexBrush
            [path] => assets/fonts/AlexBrush-Regular.ttf
        )

    [0] => Array
        (
            [index] => 0
            [name] => Arial
            [path] => assets/fonts/arial.ttf
        )

    [2] => Array
        (
            [index] => 2
            [name] => Roboto
            [path] => assets/fonts/roboto.ttf
        )

    [1] => Array
        (
            [index] => 1
            [name] => Times
            [path] => assets/fonts/times.ttf
        )

)

或者像我一样。法罗斯在评论中指出,如果你用。。。

foreach ( $fonts as $font ) {
    echo "<br/>".$font["name"];
}

<br/>AlexBrush<br/>Arial<br/>Roboto<br/>Times

可以使用array\u列使数组关联,然后使用ksort(键排序)进行排序。

$fonts = array_column($fonts, null, "name");
ksort($fonts);
$fonts = array_values($fonts);
var_dump($fonts);

array(4) {
  [0]=>
  array(3) {
    ["index"]=>
    int(3)
    ["name"]=>
    string(9) "AlexBrush"
    ["path"]=>
    string(34) "assets/fonts/AlexBrush-Regular.ttf"
  }
  [1]=>
  array(3) {
    ["index"]=>
    int(0)
    ["name"]=>
    string(5) "Arial"
    ["path"]=>
    string(22) "assets/fonts/arial.ttf"
  }
  [2]=>
  array(3) {
    ["index"]=>
    int(2)
    ["name"]=>
    string(6) "Roboto"
    ["path"]=>
    string(23) "assets/fonts/roboto.ttf"
  }
  [3]=>
  array(3) {
    ["index"]=>
    int(1)
    ["name"]=>
    string(5) "Times"
    ["path"]=>
    string(22) "assets/fonts/times.ttf"
  }
}

这意味着您可以像在问题中所做的那样迭代数组。

https://3v4l.org/pJXfp

我看到你问如何得到索引3的名字。

在这种情况下,再次使用array\u column使其与索引关联。

https://3v4l.org/nCtJf

$fonts = array_column($fonts, null, "name");
ksort($fonts);
$fonts = array_column($fonts, null, "index");

echo $fonts[3]["name"]; //AlexBrush

如果你想继续使用 for() ,实际上需要重新索引第一级键——这没什么大不了的,因为在 index 元素。

1. array_multisort(array_column($fonts, 'name'), $fonts);
2. usort($fonts, function($a, $b){return $a['name'] <=> $b['name'];});

Demo