这篇文章分为两部分,顶部是根据OP的新信息更新的答案
eatAB()
不允许或无法修改。第二个答案是原始答案,如果您有权修改函数本身,您将如何解决这个问题。
更新的答案(您缺乏修改功能的访问/权限)
因为您没有权限在内部更改函数,但您知道它的签名
eatAB(a=None,b=None)
我们想遵循这个逻辑(从问题开始):
-
如果我们传递的值是真实的(例如。
True
),我们要传递值
-
如果该值不为true,我们希望使用参数的默认值,即
None
这可以使用以下表达式轻松实现:
value if condition else otherValue
当调用函数时使用该函数时,会产生以下结果:
a = False
b = True
eatAB(a if a else None, b if b else None)
# will be the same as calling eatAB(None, True) or eatAB(b=True)
当然,如果a和b的值来自某个条件本身,则可以使用该条件。例如:
eatAB(someValue if "a" in myDictionary else None, someOtherValue if "b" in myDictionary else None)
原始答案(您可以在其中修改功能)
:
不知道具体是什么
eatAB()
或者它的确切签名,我可以推荐的最好的是以下内容。我相信你可以根据需要进行调整。
主要思想是将这种逻辑转化为
eatAB()
因为这是函数的责任,而不是调用代码的责任。注释中有解释:
# for parameters a and b to be optional as you have shown, they must have a default value
# While it's standard to use None to denote the parameter is optional, the use case shown in the question has default values where a or b are False - so we will use that here.
def eatAB(a=False, b=False):
# check if the parameters are truthy (e.g. True), in which case you would have passed them in as shown in the question.
if a:
# do some logic here for when a was a truthy value
if b:
# do some logic here for when b was a truthy value
# what exactly the eatAB function I cannot guess, but using this setup you will have the same logic as wanted in the question - without the confusing conditional block each time you call it.
# function can then be called easily, there is no need for checking parameters
eatAB(someValue, someOtherValue)
感谢Chris_Rands提出的改进建议。
