在完整文件路径中搜索用户关键字,并根据搜索结果给出输出目录或文件名。

我不知道我是否理解,但我认为这是你想要的:

filepath='D:\ABDCD\Desktop\old.net\BestchPring\Vs.net\CommanUsegftrol.ascx.cs'

def findpath(searchtext):
    path = os.path.normpath(filepath)
    while path != "":
        path, folder = os.path.split(path)
        if searchtext.lower() in folder.lower():
            return os.path.join(path, folder)
    return "Not found"

结果:

In [1]: findpath("des")
Out[1]: 'D:\ABDCD\Desktop'

In [2]: findpath("comman")
Out[2]: 'D:\ABDCD\Desktop\old.net\BestchPring\Vs.net\CommanUsegftrol.ascx.cs'

如果我理解你的问题正确,下面的代码就是你需要的。

def filter_by_keyword(directory, pattern):
    root = ...
    if os.path.dirname(directory):
        for path, subdir, files in os.walk(root):
            for fn in fnmatch.filter(files, pattern):
                print('Matched variant found in "{}", fn: "{}"'.format(path, fn))